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soldi70 [24.7K]
3 years ago
11

How does water vapor get into the atmosphere?

Chemistry
1 answer:
Brums [2.3K]3 years ago
6 0

Answer:

through the water cycle

Explanation:

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As a pilot is flying in level flight at 9,500 ft, the altimeter in the instrument panel is set to a pressure of 29.48 mm of Hg.
bearhunter [10]

Answer:

from the ideal gas law, P2 /P1 = T2 /T1 for the same volume and quantity of gas. P2 = (758 mmHg) (45 +273 K) / (15 +273K) = 837 mmHg.

Explanation:

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73g of HCL in 2.00l of HCL solution
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What is your question?
8 0
3 years ago
Physical science!!! please help
IgorLugansk [536]

Answer:

The correct answer is : No, because there are 4 hydrogen atoms on the reactants side and 2 on the products side.

Explanation:

NH_4NO_3\rightarrow N_2O+H_2O

The given reaction equation is not balanced because:

  • Number of hydrogen atoms  on both sides are not equal that is 4 on reactants side and 2 on products side.
  • Number of oxygen atoms on both sides are not equal that is 3 on reactants side and 2 on products side.

In a balanced chemical equation number of atoms of each elements are equal on both sides.

So, the balanced chemical equation will be:

NH_4NO_3\rightarrow N_2O+2H_2O

7 0
3 years ago
Titration of a 20.0-mL sample of acid rain required 1.7 mL of 0.0811 M NaOH to reach the end point. If we assume that the acidit
Rasek [7]

Answer:

Concentration of sulfuric acid in the acid rain sample is 0.0034467 mol/L.

Explanation:

Volume of NaOH = 1.7 ml = 0.0017 L

Molarity of NaOH = 0.0811 M

Moles of NaOH = n

0.0811 M=\frac{n}{0.0017 L}

n = 0.0001378 mol

H_2SO_4+2NaOH\rightarrow Na_2SO_4+2H_2O

According to reaction, 2 mol of NaOH neutralize 1 mol of sulfuric acid.

Then 0.0001378 mol of NaOH will neutralize:

\frac{1}{2}\times 0.0001378 mol=6.8935\times 10^{-5} mol of sulfuric acid.

Concentration of sulfuric acid in the acid rain sample: x

x=\frac{6.8935\times 10^{-5}}{0.02 L}=0.0034467 mol/L

Concentration of sulfuric acid in the acid rain sample is 0.0034467 mol/L.

7 0
3 years ago
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