Answer:
The answer to your question is 2.92 x 10⁻⁶ g
Explanation:
Data
mass of K = ?
atoms of K = 4.50 x 10¹⁶
Process
To answer this question just remember that the atomic mass of any element is equivalent to Avogadro's number.
1.- Look for the atomic number of Potassium
Atomic number = 39.10 g
2.- Use proportions and cross multiplication
39.10 g of K --------------- 6.023 x 10²³ atoms
x ----------------4.50 x 10¹⁶ atoms
x = (4.50 x 10¹⁶ x 39.10) / 6.023 x 10²³
-Simplify
x = 1.7595 x 10¹⁸ / 6.023 x 10²³
-Result
x = 2.92 x 10⁻⁶ g
The volume of a gas that occupies 9 L at a temperature of 325K is 12.46L.
<h3>How to calculate volume?</h3>
The volume of a given gas can be calculated using the following Charle's law equation:
V1/T1 = V2/T2
Where;
- T1 = initial temperature
- T2 = final temperature
- V1 = initial volume
- V2 = final volume
- V1 = 9L
- V2 = ?
- T1 = 325K
- T2 = 450K
9/325 = V2/450
325V2 = 4050
V2 = 4050/325
V2 = 12.46L
Therefore, the volume of a gas that occupies 9 L at a temperature of 325K is 12.46L.
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Answer:
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Answer:
V₂ = 18.13 L
Explanation:
Given data:
Mole of gas = 1 mol
Initial temperature = 273 K
Initial pressure = 1 atm
Final volume = ?
Final temperature = -41°C (-41+273 = 232 K)
Final pressure = 805 mmHg (805/760 = 1.05 atm)
Solution:
First of all we will calculate the initial volume of gas.
PV = nRT
V = nRT/P
V = 1 mol × 0.0821 mol.L/atm.K × 273 K / 1 atm
V = 22.4 L/atm / 1 atm
V = 22.4 L ( initial volume)
Now we will determine the final volume by using equation,
P₁V₁/T₁ = P₂V₂/T₂
P₁ = Initial pressure
V₁ = Initial volume
T₁ = Initial temperature
P₂ = Final pressure
V₂ = Final volume
T₂ = Final temperature
Now we will put the values.
V₂ = P₁V₁ T₂/ T₁ P₂
V₂ = 1 atm × 22.4 L × 232 K / 273 K × 1.05 atm
V₂ = 5196.8 atm .L. K / 286.65 atm.K
V₂ = 18.13 L
