An object with charge -4.0μC is placed between a positively charged object to the
1 answer:
The net force on the -4.0μC object as a result of this net field will be -10.4 N.
<h3>What is the charge?</h3>
The matter has an electric charge when it is exposed to an electromagnetic field is known as a charge.
The electric field intensity is found as the force per unit charge.
Electric field intensity on the positive charge:
Electric field intensity on the negative charge:
The net charge is the algebraic sum of the two charges;
Hence, as a result of this net field, the net force on the -4.0C object will be -10.4 N.
To learn more about the charge refer to the link;
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Answer:
d. A projectile with a horizontal component of motion will have a constant horizontal velocity.
f. The horizontal velocity of a projectile is unaffected by the vertical velocity; these two components of motion are independent of each other.
g. The horizontal displacement of a projectile is dependent upon the time of flight and the initial horizontal velocity.
h. The final horizontal velocity of a projectile is always equal to the initial horizontal velocity.
Explanation:
When we are dealing with parabolic motion, the x-component of the velocity remains the same (hence, in the case of the horizontal component, the acceleration will always be zero), <u>while the y-component always change because it is affected by the acceleration due gravity that acts verticaly.</u>
On the other hand, the horizontal displacement of the projectile is mathematically expressed as:
Where:
is the projectile's horizontal component of the initial velocity
is the time the parabolic motion lasts
This means <u>the projectile's horizontal displacement is directly proportional to the horizontal component of the initial velocity and the total time the projectile describes the parabolic motion</u>.
Of course, all of this considerations are assuming this is an ideal parabolic path and there is no air resistance.
Answer:
1170 Kelvin/meter
Explanation:
See attached pictures.
