Question

An object with charge -4.0μC is placed between a positively charged object to the

Answer 1

The net force on the -4.0μC object as a result of this net field will be -10.4 N.

What is the charge?

The matter has an electric charge when it is exposed to an electromagnetic field is known as a charge.

The electric field intensity is found as the force per unit charge.

Electric field intensity on the positive charge:

$\rm E_1 = \frac{F_1}{Q} \\\\\ \rm 1.2 N/C = \frac{F_1}{ -4.0 \mu C} \\\\ F_1 = - 4.8 \ N$

Electric field intensity on the negative charge:

$\rm E_2 = \frac{F_2}{Q} \\\\\ \rm 1.4 \ N/C = \frac{F_1}{ -4.0 \mu C} \\\\ F_2 = - 5.6 \ N$

The net charge is the algebraic sum of the two charges;

$\rm F_{net}=F_1+F_2 \\\\ F_{net}= -4.8 -5.6 \\\\ F_{net}=-10.4 \ N$

Hence, as a result of this net field, the net force on the -4.0C object will be -10.4 N.

To learn more about the charge refer to the link;

brainly.com/question/24391667

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