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ladessa [460]
3 years ago
8

Write and solve the system of linear equations described by the application and then answer the question. One hundred sixty feet

of fencing encloses a rectangular garden on three sides. One side of the garden is the side of a barn and requires no fencing. The longer side is parallel to the barn.
If the length of the longer side of the rectangle is twice the width, what are the dimensions of the garden?
Mathematics
1 answer:
Lena [83]3 years ago
3 0

Answer:

80 ft x 40 ft

Step-by-step explanation:

Let 'L' be the length of the longer side and 'W' be the length of the shorter side (or the width).

The equations that compose the linear system are:

L+2W=160\\L=2W

Solving the system:

L+L=160\\L=80\\W=\frac{L}{2}\\W=40

The garden is a rectangle with dimensions 80 ft x 40 ft.

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Read 2 more answers
Need some help please <br><img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B11%7D%7B15%7D%20%20%2B%20%28%20-%20%20%5Cfrac%7B3%7D%7B
emmasim [6.3K]

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\frac{11}{15}  + (- \frac{3}{4} )\\

= \frac{11}{15}  -  \frac{3}{4}\\

= \frac{44}{60}  -  \frac{45}{60}\\  (find LCM of demoninators)

= \frac{44-45}{60}\\

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