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ycow [4]
3 years ago
13

1.3485 divided by 0.31 please

Mathematics
2 answers:
levacccp [35]3 years ago
6 0
The Answer Is 4.35. Hope This Helps.
enyata [817]3 years ago
4 0
In the fraction form it is 87/20and 
in the decimal form is 4.35
hope this was helpful ☺
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HELP!!!!!!!!!!!!!!!!!!!! ASAP!!!!!!!!!!!!!!!!!!!!!!!
Pani-rosa [81]

Answer:

x < 9

Step-by-step explanation:

subtract 7 from both sides of the inequality

- 4x > - 36 ( divide both sides by - 4 )

When multiplying/dividing by a negative quantity the symbol is reversed

x < 9 ← note reversal of symbol


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Your last doctor’s visit cost $105. Health insurance through your employer paid $84, and you paid the remaining $21. What percen
koban [17]

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You paid 20% of the cost.

Step-by-step explanation:

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2 years ago
The sum of 4 and y divided by 5 equal to 9. Find the value of y.​<br>pls a better solution
rosijanka [135]

Answer:

y=41

Step-by-step explanation:

Let us start by writing an equation. <em>4 plus y divided by 5 equals to 9</em> :

\frac{4+y}{5}=9

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4+y=45\\y=41

<em>I hope this helps! Let me know if you have any questions :)</em>

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3 years ago
Mary lost 30 lbs. Before her diet she weighed 180 pounds. What is the percent of change?​
Anestetic [448]

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The percent change is 16.67

Step-by-step explanation:

7 0
3 years ago
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Solve the equation for x∈Z <br><br>-x² +8x -14 ≥ 0
kenny6666 [7]
ax^2+bx+c=0\\\Delta=b^2-4ac\\if\ \Delta < 0\ then\ no\ solutions\\if\ \Delta=0\ then\ one\ solution:x=\frac{-b}{2a}\\if\ \Delta > 0\ then\ two\ solutions:x=\frac{-b\pm\sqrt\Delta}{2a}\\================================\\\\-x^2+8x-14\geq0\ \ \ \ |multiply\ both\ sides\ by\ (-1)\ \{change\ \geq\ on\ \leq\}\\\\x^2-8x+14\leq0\\\\a=1;\ b=-8;\ c=14\\\\\Delta=(-8)^2-4\cdot1\cdot14=64-56=8 > 0\\\sqrt\Delta=\sqrt8=\sqrt{4\cdot2}=\sqrt4\cdot\sqrt2=2\sqrt2

x_1=\frac{-(-8)-2\sqrt2}{2\cdot1}=\frac{8-2\sqrt2}{2}=\frac{8}{2}-\frac{2\sqrt2}{2}=\boxed{4-\sqrt2}\\\\x_2=\frac{-(-8)+2\sqrt2}{2\cdot1}=\frac{8+2\sqrt2}{2}=\frac{8}{2}+\frac{2\sqrt2}{2}=\boxed{4+\sqrt2}\\\\============================

ax^2+bx+c=0\\\\if\ a > 0\ then\ the\ parabola\ o pen\ up\\if\ a < 0\ then\ the\ parabola\ o pen\ down\\========================\\\\a=1 > 0-therefore\ o pen\ up\ (look\ at\ the\ picture)\\\\===============================\\\\Answer:x\in\left


Solutions\ in\ \mathbb{Z}:\\\\\sqrt2\approx1.4\\\\threfore:4-\sqrt2\approx4-1.4=2.6\ and\ 4+\sqrt2\approx4+1.4=5.4\\\\look\ at\ the\ second\ picture:x=3\ or\ x=4\ or\ x=5\ (x\in\{3;\ 4;\ 5\})

6 0
3 years ago
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