X^2+16-38=0
find what 2 numbers multiply to get -38 and add to get 16
find factors of 38
2 times 19
there is no way to use common factor so use quadratic formula which is
x=

or x=

ax^2+bx+c=0 subsitte
a=1
b=16
c=-38
subsitute

=

=

=

=

so the answers for x are

and

which are aprox -2.099504938362 and +18.099504938362
so it would be
(x-[-8+√102])(x+[8+√102])=0
First you want to write 7x as a sum or difference: 15x-8x
Now, the expression would look like this: 10x^2+15x-8x-12
Next, factor out the 5x and -4 from the expression: 5x(2x+3)-4(2x+3)
Now, factor out the 2x+3 from the expression and you have your answer:
(2x+3)(5x-4)
Answer:
yes they can
Step-by-step explanation:
I guess that's all you can do
to find a and b you need more information
b=-a -> a (x-3)-a (x-2)=3
a [x-3-(x-2)]=3
a (x-3-x+2)=3
a*(-1)=3
a=3:(-1)
a=-3
b=-a=-(-3)=3