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Alecsey [184]
2 years ago
8

Find the area of the shape

Mathematics
1 answer:
weqwewe [10]2 years ago
5 0

Answer:

50²yards

Step-by-step explanation:

Cut the shape into 2 peices. The square has a length of 6yd and base of 8yd. bh=48².The little triangle has a base of 4yd and a length of 6yd. bh/2=12².

48 plus 12 = 50yd²

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find the digit in units place in the expansion of the following: 1) 2¹⁹⁶⁷ 2) 3¹⁹⁶⁹ 3)4¹⁹⁷⁰ 4) 4¹⁹⁷¹ 5) 5⁵⁵⁵ 6) 6¹⁰⁰⁰ 7) 7²⁰⁰⁷ 8)
diamong [38]

Answer:

troll

Step-by-step explanation:

troll!!!!!!!!!!!!!!!!!!!!!!

5 0
3 years ago
Is 5/6 x 2/3 equal to greater than or less than 2/3
viva [34]
Greater than obviously
7 0
3 years ago
Read 2 more answers
I will give extra points please help
pav-90 [236]

Answer:

2

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Someone please be awesome and help me please :(
solong [7]

Answer:

(x+\frac{b}{2a})^2+(\frac{4ac}{4a^2}-\frac{b^2}{4a^2})=0

(x+\frac{b}{2a})^2=\frac{b^2-4ac}{4a^2}

x=\frac{-b}{2a} \pm \frac{\sqrt{b^2-4ac}}{2a}

Step-by-step explanation:

x^2+\frac{b}{a}x+\frac{c}{a}=0

They wanted to complete the square so they took the thing in front of x and divided by 2 then squared.  Whatever you add in, you must take out.

x^2+\frac{b}{a}x+(\frac{b}{2a})^2+\frac{c}{a}-(\frac{b}{2a})^2=0

Now we are read to write that one part (the first three terms together) as a square:

(x+\frac{b}{2a})^2+\frac{c}{a}-(\frac{b}{2a})^2=0

I don't see this but what happens if we find a common denominator for those 2 terms after the square.  (b/2a)^2=b^2/4a^2 so we need to multiply that one fraction by 4a/4a.

(x+\frac{b}{2a})^2+\frac{4ac}{4a^2}-\frac{b^2}{4a^2}=0

They put it in ( )

(x+\frac{b}{2a})^2+(\frac{4ac}{4a^2}-\frac{b^2}{4a^2})=0

I'm going to go ahead and combine those fractions now:

(x+\frac{b}{2a})^2+(\frac{-b^2+4ac}{4a^2})=0

I'm going to factor out a -1 in the second term ( the one in the second ( ) ):

(x+\frac{b}{2a})^2-(\frac{b^2-4ac}{4a^2})=0

Now I'm going to add (b^2-4ac)/(4a^2) on both sides:

(x+\frac{b}{2a})^2=\frac{b^2-4ac}{4a^2}

I'm going to square root both sides to rid of the square on the x+b/(2a) part:

x+\frac{b}{2a}=\pm \sqrt{\frac{b^2-4ac}{4a^2}}

x+\frac{b}{2a}=\pm \frac{\sqrt{b^2-4ac}}{2a}

Now subtract b/(2a) on both sides:

x=\frac{-b}{2a} \pm \frac{\sqrt{b^2-4ac}}{2a}

Combine the fractions (they have the same denominator):

x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}

6 0
3 years ago
2x + y = 3
sergejj [24]

Hey there!

First, multiply the second equation by -2 as the problem states. When you multiply the second equation by -2, you get:

-2x+4y=2

Now, add this equation to the first equation in which you simply combine like terms:

2x+y=3

+

-2x+4y=2

=

5y= 5

In conclusion, the correct answer would be the first choice.

4 0
3 years ago
Read 2 more answers
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