Let V = the launch velocity
Let θ = the launch angle
Let d = the horizontal distance traveled
Ignore air resistance.
The horizontal component of velocity is
u = V cos θ
The time of flight is
t = d/(V cosθ) = (d/V) secθ
Create a table of θ versus t as shown below.
θ t/(d/V)
---- ----------
45 1.4142
40 1.3054
35 1.2208
30 1.1547
The graph shows that as the launch angle decreases below 45°, the time of flight decreases.
Therefore arrow b (θ < 45°) arrives first.
Answer: Arrow b arrives first.
If you are working with time or days, you can't put in a negative value because if you are doing an experiment, you can't go back in time to do that experiment to gather data. (Time for the most part considered to be an input value so that's why I used it as an example.)
Answer: 12
According to the box plot, the medians are marked in the middle (those middle lines). Find the difference by subtracting 84 - 73 = 12
Hope that helps! ★ If you have further questions about this question or need more help, feel free to comment below or leave me a PM. -UnicornFudge aka Nadia
Answer:20.00
Step-by-step explanation: next time include the table but i managed to find it anyway
Answer:
150 miles
Step-by-step explanation:
Abdul's average speed in heavy traffic = 30 mph
Time Spent in heavy traffic = 1 hour
Distance covered in heavy traffic =Speed in heavy traffic X Time Spent in Heavy Traffic
=30 X 1 =30 miles
Abdul's Average speed in light traffic= 60 mph
Time Spent in light traffic = 2 hours
Distance covered in light traffic =Speed in light traffic X Time Spent in light Traffic = 60 X 2 =120 miles
Total Distance covered by Abdul = Distance covered in heavy traffic + Distance covered in light traffic
=30 + 120
=150 miles
