The weight of the heaviest fish is 15.2 pounds
•since the average is 13.2, we will multiply 13.2 by 5 because there is 5 total fish. this makes a total of 66 pounds between the 5 fish. then we will subtract the weights of the 4 fish given to us from the total of 66, to get the remaining weight of 15.2 pounds. that also happens to be the heaviest weight, so 15.2 is the correct answer
Answer:
Step-by-step explanation:
1²+16²=1+256=257≠289(17²)
2²+16²=4+256=260≠17²
3²+16²=9+256=265≠17²
4²+16²=16+256=272≠17²
5²+16²=25+256=281≠17²
6²+16²=36+256=292>17²
6²+15²=36+225=261≠17²
7²+15²=49+225=274≠17²
8²+15²=64+225=289=17²
9²+14²=81+196=277≠17²
10²+14^2=100+196>289
10²+13²=100+169=269≠17²
11²+13³=121+169=290>17²
11²+12²=121+144=265≠17²
12²+12²=144+144=288≠17²
so only integer values are 8²+15²=17²
(x+4)²+(y-7)²=17²
if x+4=8
x=8-4=4
y-7=15
y=15+7=22
so q is (4,22)
if x+4=15
x=15-4=11
y-7=8
y=8+7=15
point is (11,15)
You could divide the result (14) by 7
The answer to the first B one is horizontal translation 1 to the right because the -1 is inside the quantity.
2nd g(x)=3x^2+8