Question

Find n(A x B x C) when A = {a,b,c} B = {p,q} C = {x,y}

Answer 1

Using the Fundamental Counting Theorem, considering the cardinality of each set, it is found that n(A x B x C) = 12.

What is the Fundamental Counting Theorem?

It is a theorem that states that if there are n things, each with $n_1, n_2, \cdots, n_n$ ways to be done, each thing independent of the other, the number of ways they can be done is:

$N = n_1 \times n_2 \times \cdots \times n_n$

In this problem, we have that:

• $nA = n_1 = 3$.

• $nB = n_2 = 2$.

• $nC = n_3 = 2$.

Hence, applying the Theorem:

n(A x B x C) = 3 x 2 x 2 = 12.

More can be learned about the Fundamental Counting Theorem at brainly.com/question/24314866

#SPJ1