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harina [27]
3 years ago
15

Help pleaseeeeee 4x (-3/8)=

Mathematics
1 answer:
Murrr4er [49]3 years ago
7 0

Answer:

-3x/2

Step-by-step explanation:

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6th grade math, help me please.
kirill115 [55]

Answer:

1:3

Step-by-step explanation:

3/3=1

9/3=6

3 0
4 years ago
Read 2 more answers
What is the dashed green part of the figure below?
Shtirlitz [24]
The actual question is not visible
6 0
3 years ago
Do you tailgate the car in front of you? About 35% of all drivers will tailgate before passing, thinking they can make the car i
Vesna [10]

Answer:

(a) The histogram is shown below.

(b) E (X) = 4.2

(c) SD (X) = 2.73

Step-by-step explanation:

Let <em>X</em> = <em>r</em><em> </em>= a driver will tailgate the car in front of him before passing.

The probability that a driver will tailgate the car in front of him before passing is, P (X) = <em>p</em> = 0.35.

The sample selected is of size <em>n</em> = 12.

The random variable <em>X</em> follows a Binomial distribution with parameters <em>n</em> = 12 and <em>p</em> = 0.35.

The probability function of a binomial random variable is:

P(X=x)={n\choose x}p^{x}(1-p)^{n-x}

(a)

For <em>X</em> = 0 the probability is:

P(X=0)={12\choose 0}(0.35)^{0}(1-0.35)^{12-0}=0.006

For <em>X</em> = 1 the probability is:

P(X=1)={12\choose 1}(0.35)^{1}(1-0.35)^{12-1}=0.037

For <em>X</em> = 2 the probability is:

P(X=2)={12\choose 2}(0.35)^{2}(1-0.35)^{12-2}=0.109

Similarly the remaining probabilities will be computed.

The probability distribution table is shown below.

The histogram is also shown below.

(b)

The expected value of a Binomial distribution is:

E(X)=np

The expected number of vehicles out of 12 that will tailgate is:

E(X)=np=12\times0.35=4.2

Thus, the expected number of vehicles out of 12 that will tailgate is 4.2.

(c)

The standard deviation of a Binomial distribution is:

SD(X)=np(1-p)

The standard deviation of vehicles out of 12 that will tailgate is:

SD(X)=np(1-p)=12\times0.35\times(1-0.35)=2.73\\

Thus, the standard deviation of vehicles out of 12 that will tailgate is 2.73.

4 0
3 years ago
in a recent semester at a local university 520 students enrolled in both general chemistry and calculus 1. Of these students 88
IceJOKER [234]

Let Ch and C denote the events of a student receiving an A in <u>ch</u>emistry or <u>c</u>alculus, respectively. We're given that

P(Ch) = 88/520

P(C) = 76/520

P(Ch and C) = 31/520

and we want to find P(Ch or C).

Using the inclusion/exclusion principle, we have

P(Ch or C) = P(Ch) + P(C) - P(Ch and C)

P(Ch or C) = 88/520 + 76/520 - 31/520

P(Ch or C) = 133/520

6 0
3 years ago
Sorry i have another question what is the inequality of 8x−8≤−72.
vova2212 [387]

That answer is x≤−8


Inequality:

8x−8≤−72


Step number  1:  You have to Add 8 to both sides.

8x−8+8≤−72+8

8x≤−64



Step number 2: You have to Divide both sides by 8.

8x /8  ≤  −64 / 8


Ur Answer:

x≤−8


Hope this helps :)


7 0
4 years ago
Read 2 more answers
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