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2 years ago

10

What is the area of the following circle? Either enter an exact answer in terms of π or use 3.14 for π and enter your answer as

a decimal. d=10

2 answers:

Ipatiy [6.2K]2 years ago

8 0

The area is ~ 78.54

ASHA 777 [7]2 years ago

5 0

The radius is 10/2 = 5, so the area is 5^2 * pi = 25pi.

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*****WILL GIVE BRAINLEST IF CORRECT******

PSYCHO15rus [73]

Conner's work is correct. To combine and make it simple, you Multiply:

(3^5+9)+(6^8+10) which will equal 3^14 6^18.

But Jane's work, instead of adding, Jane multiplies. So, Conner is correct.

Hope that helped!

5 0

3 years ago

Please find the area of the figure!!

Murrr4er [49]

The figure consists of a rectangle and a circle.

first lets find the sides of the triangle

sides of the triangle are 4+4=8 and 3+1=4

therefore area of the rectangle is 8*4=32

now area of semicircle =πr^2/2 = π2^2/2=2π=6.3

we have to add the area of rectangle with the area of semicircle

this is because it the given figure no part of area of circle and rectangle are in common.

therefore total area of given figure = 32+6.3=38.3

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3 years ago

A shopper at a local supermarket spent the following amounts in her last eight trips to the store: $32.92 $14.14 $30.80 $28.34 $

alexdok [17]

Answer:

$75.58

The amount spent of $75.58 is most likely an outlier

Step-by-step explanation:

An outliers are unusual values in a dataset, they are data values that are extremely higher or extremely lower when compared to the other values in a data (data points that are far from other data points)

For the case above, give a dataset;

$32.92 $14.14 $30.80 $28.34 $75.58 $36.33 $33.51 $22.94

$75.58 is extremely far from other value. So $75.58 is an outlier in the given dataset.

7 0

3 years ago

Quais os numeros naturais entre 893 e 991 que divididos por 23 deixam sempre o maior resto possível

Alla [95]

English please ? I only speak English but I’m sure I can help.

6 0

2 years ago

Find the solution of the problem (1 3. (2 cos x - y sin x)dx + (cos x + sin y)dy=0.

lakkis [162]

Answer:

$2*sin(x)+y*cos(x)-cos(y)=C_1$

Step-by-step explanation:

Let:

$P(x,y)=2*cos(x)-y*sin(x)$

$Q(x,y)=cos(x)+sin(y)$

This is an exact differential equation because:

$\frac{\partial P(x,y)}{\partial y} =-sin(x)$

$\frac{\partial Q(x,y)}{\partial x}=-sin(x)$

With this in mind let's define f(x,y) such that:

$\frac{\partial f(x,y)}{\partial x}=P(x,y)$

and

$\frac{\partial f(x,y)}{\partial y}=Q(x,y)$

So, the solution will be given by f(x,y)=C1, C1=arbitrary constant

Now, integrate $\frac{\partial f(x,y)}{\partial x}$ with respect to x in order to find f(x,y)

$f(x,y)=\int\ 2*cos(x)-y*sin(x)\, dx =2*sin(x)+y*cos(x)+g(y)$

where g(y) is an arbitrary function of y

Let's differentiate f(x,y) with respect to y in order to find g(y):

$\frac{\partial f(x,y)}{\partial y}=\frac{\partial }{\partial y} (2*sin(x)+y*cos(x)+g(y))=cos(x)+\frac{dg(y)}{dy}$

Now, let's replace the previous result into $\frac{\partial f(x,y)}{\partial y}=Q(x,y)$ :

$cos(x)+\frac{dg(y)}{dy}=cos(x)+sin(y)$

Solving for $\frac{dg(y)}{dy}$

$\frac{dg(y)}{dy}=sin(y)$

Integrating both sides with respect to y:

$g(y)=\int\ sin(y) \, dy =-cos(y)$

Replacing this result into f(x,y)

$f(x,y)=2*sin(x)+y*cos(x)-cos(y)$

Finally the solution is f(x,y)=C1 :

$2*sin(x)+y*cos(x)-cos(y)=C_1$

7 0

3 years ago