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1 year ago

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3 lines are shown. A line with points T, R, W intersects with a line with points S, R, V at point R. Another line extends from p

oint R to point U in between angle V R W.
Which pair of angles are vertical angles?

1 answer:

Mamont248 [21]1 year ago

6 0

Answer:

∠TRV and ∠WRS or ∠TRS and ∠WRV

Step-by-step explanation:

Vertical angles are angles that share a vertex and have sides that are opposite rays. That is, the opposites of the rays that form one of the angles are the rays that form the other angle.

__

Where lines cross, two pairs of vertical angles are formed. In your diagram, those pairs are ...

∠TRV and ∠WRS . . . . one vertical angle pair

∠TRS and ∠WRV . . . . another vertical angle pair

_____

<em>Additional comment</em>

In this diagram, the ray RU is of no consequence with respect to any vertical angles. It can be ignored.

The vertical angles will each have one red ray and one blue ray as sides. These rays have end point R. No sides are shared.

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Can anyone please help me with these

DochEvi [55]

Answer: Natural/Counting = 1, 0, 6, 3,

Whole = 1234, 135

Integers = -42,260, -97

Rational = 0.5432, 14.4, 6.2, 6.5892,

-14.4, 7.7777777, -13.574,

3.14, 0.4, 6.2, 0.4, 0.34,

12/6, -8/4, -10/5, -3/4, -3/8,

3/7, -4/8, 6/2, -8/4

Irrational = √34, -√34, -√ 36, 2π, √81,

√300, √1, π.

;Hope this Helped with both Pages:)

4 0

3 years ago

Write the equation of the circle below to complete the square. Also determine the area of the circle.

diamong [38]

Answer: $(x-7)^2+(y+2)^2=11^2$ ; $A=121\pi$

Step-by-step explanation:

I have never done a problem like this, so this is my first time attempting it.

The standard form for the equation of a circle is:

$(x-a)^2+(y-b)^2=r^2$

Begin by grouping the 'x' terms and 'y' terms:

$(x^2-14x)+(y^2+4y-68)=0$

Complete the square for the second polynomial:

$(\frac{b}{2} )^2=(\frac{4}{2} )^2=4$

$(x^2-14x)+(y^2+4y+4-4-68)=0$

$(x^2-14x)+(y^2+4y+4)-4-68=0$

$(x^2-14x)+(y^2+4y+4)-72=0$

$(x^2-14x)+(y+2)^2-72=0$

Do the exact same process with the other polynomial:

$(x^2-14x-72)+(y+2)^2=0$

Complete the square:

$(\frac{14}{2} )^2=49$

$(x^2-14x+49-49-72)+(y+2)^2=0$

$(x^2-14x+49)-49-72+(y+2)^2=0$

$(x^2-14x+49)-121+(y+2)^2=0$

$(x-7)^2-121+(y+2)^2=0$

Bring the 121 to the other side to get:

$(x-7)^2+(y+2)^2=121$

$(x-7)^2+(y+2)^2=11^2$

The above expression is the equation of our circle in standard form. It is centered at the coordinates (7, -2) and has a radius of 11 units. The area of a circle if given by:

$A=\pi r^2=121\pi$

8 0

2 years ago

Need math help for this

Burka [1]

Answer:

<h2>In the attachment</h2>

Step-by-step explanation:

The point-slope form of an equation of a line:

$y-y_1=m(x-x_1)$

m - slope

(x₁, y₁) - point

We have the equation:

$y-5=-\dfrac{2}{3}(x+9)\\\\y-5=-\dfrac{2}{3}(x-(-9))$

Therefore we have

the slope m = -2/3

and the point (-9, 5)

A slope

$m=\dfrac{rise}{run}$

rise = -2

run = 3

From the point (-9, 5) ⇒ 2 units down and 3 units to the right.

7 0

3 years ago

Match the following equation to the correct situation.

uranmaximum [27]

Answer:

The equation given in the question matches the situation C.

Step-by-step explanation:

A. The amount that Cindy paid for books was 15% of p i.e. it is only $\frac{15p}{100} = 0.15p$

B. The amount is given to a charity after saving 15% of p. That means if p is the amount of charity, then there were a savings of 15% of p.

Therefore, the total charity payment after savings = p - 15% of p = $p - \frac{15p}{100} = p - 0.15p = 0.85p$

C. The amount that Sandy paid for a shirt with 15% tax on p.

Therefore, if the price of a shirt is p, then total payment of Sandy after tax is = p + 15% of p = $(p + \frac{15p}{100}) = p + 0.15p = 1.15p$

Hence, the equation given in the question matches the situation C. (Answer)

8 0

3 years ago

(2.5×10^−10)(7×10^−6)

Nataly [62]

<span>(2.5×10^−10)(7×10^−6)
= (2.5 x 7) (</span>10^−10 x 10^−6)
= 17.5 x 10^-16
= 1.75 x 10^-15

answer
<span>B. 1.75×10^−15 </span>

6 0

3 years ago