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Verdich [7]
2 years ago
7

3 lines are shown. A line with points T, R, W intersects with a line with points S, R, V at point R. Another line extends from p

oint R to point U in between angle V R W.
Which pair of angles are vertical angles?
Mathematics
1 answer:
Mamont248 [21]2 years ago
6 0

Answer:

  ∠TRV and ∠WRS  or  ∠TRS and ∠WRV

Step-by-step explanation:

Vertical angles are angles that share a vertex and have sides that are opposite rays. That is, the opposites of the rays that form one of the angles are the rays that form the other angle.

__

Where lines cross, two pairs of vertical angles are formed. In your diagram, those pairs are ...

  ∠TRV and ∠WRS . . . . one vertical angle pair

  ∠TRS and ∠WRV . . . . another vertical angle pair

_____

<em>Additional comment</em>

In this diagram, the ray RU is of no consequence with respect to any vertical angles. It can be ignored.

The vertical angles will each have one red ray and one blue ray as sides. These rays have end point R. No sides are shared.

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Suppose that the national average for the math portion of the College Board's SAT is 510. The College Board periodically rescale
Marta_Voda [28]

Answer:

a) 0.1587 b) 0.023 c) 0.1587 d) 1.15 e)-0.95      

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 510

Standard Deviation, σ = 100

We are given that the distribution of SAT score is a bell shaped distribution that is a normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

a) P(score greater than 610)

P(x > 610)

P( x > 610) = P( z > \displaystyle\frac{610 - 510}{100}) = P(z > 1)

= 1 - P(z \leq 1)

Calculation the value from standard normal z table, we have,

P(x > 610) = 1 - 0.8413 = 0.1587 = 15.87\%

b) P(score greater than 710)

P(x > 710) = P(z > \displaystyle\frac{710-510}{100}) = P(z > 2)\\\\P( z > 2) = 1 - P(z \leq 2)

Calculating the value from the standard normal table we have,

1 - 0.977 = 0.023 = 2.3\%\\P( x > 710) = 2.3\%

c)P(score between 410 and 510)

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P(410 \leq x \leq 510) = 34.1\%

d) x = 625

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e) x = 415

z_{score} = \displaystyle\frac{415 - 510}{100} = \displaystyle\frac{-95}{100} = -0.95

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