When we throw an arrow by streching the string of a bow , how does the energy change take place ?
2 answers:
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Answer:
0.84 Ω
Explanation:
r = mean radius of the turn = 6.5 mm
n = number of turns of copper wire = 150
Total length of wire containing all the turns is given as
L = 2πnr
L = 2 (3.14)(150) (6.5)
L = 6123 mm
L = 6.123 m
d = diameter of the wire = 0.4 mm = 0.4 x 10⁻³ m
Area of cross-section of the wire is given as
A = (0.25) πd²
A = (0.25) (3.14) (0.4 x 10⁻³)²
A = 1.256 x 10⁻⁷ m²
ρ = resistivity of copper = 1.72 x 10⁻⁸ Ω-m
Resistance of the coil is given as
R = 0.84 Ω
Answer:
462 nm
Explanation:
Given: width of the slit, d = 5.6 × 10⁻⁴ m
Distance of the screen, D = 4.0 m
Fringe width, β = 3.3 mm = 3.3 × 10⁻³ m
First dark fringe means n =1
Wavelength of the light, λ = ?
Answer:
Part a)
Part b)
Part c)
Since horizontal speed of truck and the arrow is same so the arrow will strike at the position of the archer as they both moving with same speed
Explanation:
Part a)
As we know that the arrow moves with uniform acceleration in vertical direction so we can use kinematics in Y direction
Here we know that
since the arrow lands at the same height so its vertical displacement of whole motion is zero
so we will have
Part b)
Horizontal distance moved by the arrow
here horizontal speed of arrow is same as that of speed of truck
so we will have
Part c)
Since horizontal speed of truck and the arrow is same so the arrow will strike at the position of the archer as they both moving with same speed