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2 years ago

When we throw an arrow by streching the string of a bow , how does the energy change take place ?

2 answers:

6 0

when we throw an arrow , we first stretch the string of the bow. while stretching the string of the bow, the work done by us in stretching the bowstring gets stored as potential energy in the bow. This potential energy of the bow is transformed into kinetic energy when the bowstring is released and this gives the momentum and Kinetic energy to the arrow.

For more details for transfer of energy visit the given site link :-

https://brainly.in/question/22705654

mart [117]2 years ago

5 0

When an arrow is drawn back by a bow, the work done by us in stretching the bowstring gets stored at potential energy in the bow. This potential energy of bow is transformed into kinetic energy when the bowstring is released and this gives kinetic energy to the arrow.

All the best!

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The Heaviside function H is defined by H(t)={0 if t<0, 1 if t≥0 It is used in the study of electric circuits to represent the

Studentka2010 [4]

Answer:

$V(t)= 240V* H(t-5)$

Explanation:

The heaviside function is defined as:

$H(t) =1 \quad t\geq 0\\H(t) =0 \quad t$

so we see that the Heaviside function "switches on" when $t=0$ , and remains switched on when $t>0$

If we want our heaviside function to switch on when $t=5$ , we need the argument to the heaviside function to be 0 when $t=5$

Thus we define a function f:

$f(t) = H(t-5)$

The $-5$ term inside the heaviside function makes sure to displace the function 5 units to the right.

Now we just need to add a scale up factor of 240 V, because thats the voltage applied after the heaviside function switches on. ( $H(t-5) =1$ when $t\geq 5$ , so it becomes just a 1, which we can safely ignore.)

Therefore our final result is:

$V(t)= 240V* H(t-5)$

I have made a sketch for you, and added it as attachment.

5 0

3 years ago

when an object is charged by contact, what kind of charge does the object have compared with the charge on the on the object giv

sveta [45]

Answer:

the charge that is given by the object is positive charge and the object which is taking the charge is negetively charged

Explanation:

5 0

3 years ago

What will be the force if the particle's charge is tripled and the electric field strength is halved? Give your answer in terms

kirza4 [7]

Answer:

F' = (3/2)F

Explanation:

the formula for the electric field strength is given as follows:

E = F/q

where,

E = Electric Field Strength

F = Force due to the electric field

q = magnitude of charge experiencing the force

Therefore,

F = E q ---------------- equation (1)

Now, if we half the electric field strength and make the magnitude of charge triple its initial value. Then the force will become:

F' = (E/2)(3 q)

F' = (3/2)(E q)

using equation (1)

3 0

3 years ago

A 45.0-N force pushes a cart 12.5 meters down a hallway. What is the work done on the cart?

makvit [3.9K]

Answer:

562.5J

Explanation:

The following were obtained from the question:

F = 45N

d = 12.5m

w =?

The work done can be achieved by using

w = F x d

w = 45 x 12.5

w = 562.5J

3 0

3 years ago

A 4kg brick is dropped from the top of a building whose hight is 30m.what is the velocity with which it reaches the ground

miss Akunina [59]

Answer:

=24.25 ^−1

Explanation:

Let and be initial and final velocity of the body respectively,

be acceleration due to gravity ( 9.8^−2 ), ℎ be the height of the body.

=0 ^ −1

ℎ=30

we know that, ^2−^ 2=2ℎ

^2=2∗9.8∗30

^2=588

=24.25 ^−1

4 0

3 years ago

When we throw an arrow by streching the string of a bow , how does the energy change take place ?​

When we throw an arrow by streching the string of a bow , how does the energy change take place ?