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Paraphin [41]
3 years ago
14

1.

Physics
1 answer:
ale4655 [162]3 years ago
8 0

Answer:

5.0 atm

Explanation:

P₁V₁=P₂V₂

P₁V₁/V₂=P₂

(1)(2.5)/(0•50)=P₂

P₂=5

Pressure is now 5.0 atm

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Read 2 more answers
A shot-putter puts a shot (weight = 71.5 N) that leaves his hand at a distance of 1.84 m above the ground. (a) Find the work don
givi [52]

Answer:

a)W= - 47.19 J

b)47.19 J

Explanation:

Given that

Weight ,mg= 71.5 N

y= 1.84 m

H= 2.5

a)

The distance above the hand ,h= 2.5 - 1.84 m

   h= 0.66 m

We know that gravitaional force act in the downward direction but the displacement is in upward direction that is why work done will be negative.

W= - m g h

W= -71.5 x 0.66 J

W= - 47.19 J

b)

The potential energy at initial position = m g y

The potential energy at final position = m g H

So change in the potential energy = m g H - m g y

                                                           = mg ( H- y)

                                                           =71.5 ( 2.5 - 1.84 ) = 47.19 J

Therefore change in the potential energy = 47.19 J

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