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iVinArrow [24]
1 year ago
7

Describe the differences between the energy, spacing, andmovement of molecules in a solid, a liquid, and a gas.

Physics
1 answer:
-BARSIC- [3]1 year ago
3 0

At high speeds, gas vibrates and moves freely. The liquid vibrates, moves about, and slides past one another. Solids vibrate (jiggle) but do not move from one location to another.

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Ifa truck starts from rest and it has acceleration of 4 m/s for 5 second
yan [13]

Answer:

Distance 50m

final velocity 20ms^-1

s = ut +  \frac{1}{2} a {t}^{2}  \\  = 0 \times t +  \frac{1}{2} \times 4 \times  {5}^{2}   = 50m

v = u + at \\ v = 0 + 4 \times 5 \\ v = 20ms^{ - 1}

6 0
2 years ago
Suppose that the collector is held at a small negative voltage with respect to the grid. Will the accelerated electrons reach th
Leona [35]

Answer:

B) Yes, but only those electrons with energy greater than the potential difference established between the grid and the collector will reach the collector.

Explanation:

In the case when the collector would held at a negative voltage i.e. small with regard to grid So yes the accelerated electrons would be reach to the collecting plate as the kinetic energy would be more than the potential energy that because of negative potential

so according to the given situation, the option b is correct

And, the rest of the options are wrong

3 0
3 years ago
An electron passes through a point 2.83 cm 2.83 cm from a long straight wire as it moves at 35.5 % 35.5% of the speed of light p
igor_vitrenko [27]

Answer:

The magnitude of electron acceleration is 2.34 \times 10^{15} \frac{m}{s^{2} }

Explanation:

Given:

Distance from the wire to the field point r = 2.83 \times 10^{-2} m

Speed of electron v = 35.5 \%c

Current I = 17.7 A

For finding the acceleration,

First find the magnetic field due to wire,

  B = \frac{\mu _{o}I }{2\pi r }

Where \mu_{o} = 4\pi   \times 10^{-7}

  B = \frac{4\pi \times 10^{-7}  \times 17.7 }{2\pi (2.83 \times 10^{-2} ) }

  B = 12.50 \times 10^{-5} T

The magnetic force exerted on the electron passing through straight wire,

  F = qvB  

  F = 1.6 \times 10^{-19} \times 0.355 \times 3 \times 10^{8} \times 12.50 \times 10^{-5}

  F = 21.3 \times 10^{-16} N

From the newton's second law

  F = ma

Where m = mass of electron = 9.1 \times 10^{-31} kg

So acceleration is given by,

   a = \frac{F}{m}

   a = \frac{21.3 \times 10^{-16} }{9.1 \times 10^{-31} }

   a = 2.34 \times 10^{15} \frac{m}{s^{2} }

Therefore, the magnitude of electron acceleration is 2.34 \times 10^{15} \frac{m}{s^{2} }

7 0
2 years ago
Why does ice float on water? a.The temperature of ice is lower than the temperature of water b.The temperature of water and ice
pav-90 [236]
The density of ice is less than the density of water. C
7 0
3 years ago
A wave has a frequency of 875 hz and a wavelength of 352 m. At what speed is this wave traveling 
Sonbull [250]

Answer:

308,000 or 30.8×10^3

Explanation:

v=f×lamda

v is ?, f is 875Hz, lamda is 352m

v=875×352

v=308,000

v=30.8×10^3 m/s

5 0
2 years ago
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