Prove that for a triple element x, y, z the distributive law is always satisfied if one of the elements equals 0 or 1, or if two
of the elements are equal.
1 answer:
The distributive law is satisfied if the numbers 1,2, and 3 are used as multyplying factors.
<h3>What is the distributive law?</h3>
This is basic mathematical law that states:
- A multiplied by (b+c) equals (a x b) + (a x c)
<h3>Is this law satisfied if there are three numbers involved?</h3>
The law is always satisfied if one of the numbers is 1. Here is an example
or
- (2x1) + (2x2) + (2x3)
- 2+4+6 = 12
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Remember
difference of 2 perfect squares
a^2-b^2=(a-b)(a+b)
(x)^2-(7)^2=(x-7)(x+7)
set to zero
x-7=0
x=7
x+7=0
x=-7
x=-7 or 7
Answer:
<h2> 380 candy bars</h2>
Step-by-step explanation:
Step one:
we are told that the expression for profit is
-----------------1
the above equation represents the situation
<u>given</u>
profit is $950
<u>Required</u>
n=number of bars
950=1.25n-475
collect like terms
950-475=1.25n
475=1.25n
divide both sides by 1.25
n=475/1.25
n= 380candy bars
Answer:
hi shawty
Step-by-step explanation:
woa me when lesbain
1: 8:1
2: 2/4:3/4
3: 1:2
4: 32/4:3/4
Answer:
The answer would be the third one shaded circle at -1 arrow goes left.
