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irinina [24]
3 years ago
11

Write an equation in slope-intercept form of the line through (1,3) and (-3,7)

Mathematics
2 answers:
kupik [55]3 years ago
8 0
Y=-X+4 finding the y intercept, b and slope, mx thus y=mx+b
Brums [2.3K]3 years ago
6 0
Find the slope, then use substitute the slope and one of the given points into slope-intercept form.

Slope is change in y over change in x. (7-3)/(-3-1)=-1

Slope-inttercept form is y = mx+b.
3 = -1(1)+b
b=4

y = -x + 4
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Evaluate the following expression.<br> 12÷4×32+(4−2)5
sergij07 [2.7K]

Answer:

answer is 111

Step-by-step explanation:

4 0
3 years ago
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Beth planted 35 flower seeds three out of the five seeds sprouted. How many seeds sprouted in all
ioda
21. 5x7 is 35. 3x7 is 21
8 0
3 years ago
The vertex of the parabola below is at the point (1,3), and the point (2,6) is
Inessa05 [86]

Answer:

B. y=3(x-1)2 + 3

Step-by-step explanation:

Given that

vertex of the parabola is at the point (1,3)

let's verify, if the option B is the correct equation of the parabola.

y=3(x-1)^2 + 3\\ \\y=3(x^2+1-2x) + 3\\\\y=3x^2+3-6x + 3\\\\y=3x^2-6x + 6....Eq1

comparing to standard equationof parabola (standard quadratic equation), we get

a=3, b=-6 and c=6

to find the vertex we use formula for x- coordinate as x=-b/2a

x=-(-6)/2(3)\\\\x=6/6\\x=1

to find y put x=1 in the Eq1, we get

y=3(1)^2-6(1)+6\\\\y=3-6+6\\\\y=3

vertex =(x,y) = (1, 3)

thus vertex of the parabola from the equation y=3(x-1)2 + 3 is (1,3), thus verified

7 0
3 years ago
Find the 6th term of the arithmetic sequence X – 9, -X – 11, -3.3 – 13, ...
MrMuchimi

Answer:

-13x-23

Step-by-step explanation:

Given sequence:  x-9, -x-11, -3x-13

Therefore,

  • a_1=x-9
  • a_2=-x-11
  • a_3=-3x-13

General form of an arithmetic sequence: a_n=a+(n-1)d

(where a is the first term and d is the common difference)

To find the common difference, subtract a term from the next term:

\begin{aligned}d & =a_2-a_1\\ & =(-x-11)-(x-9)\\ & = -x-11-x+9\\ & = -2x-2\end{aligned}

Therefore,

a_n & =(x-9)+(n-1)(-2x-2)

To find the 6th term, input n = 6 into the equation:

\begin{aligned}\implies a_6 & =(x-9)+(6-1)(-2x-2)\\ & = (x-9)+7(-2x-2)\\ & = x-9-14x-14\\ & = -13x-23\end{aligned}

3 0
2 years ago
There are 100 people in a wedding house, including children, men and women, and there are 100 pappadas to give with Sadya Te.
olga nikolaevna [1]

Answer:

Two possible sets of answers.

5 men, 11 women and 42 children, or

10 men, 2 women and 88 children

Selamat Sadhya!

Step-by-step explanation:

M = number of men

W = number of women

100-M-W = number of children

Total number of pappadas

5M+3W+(100-M-W)/2 = 100

Solve for W

W = (100-9M)/5 .......................(1)

Examine equation (1).

In order to have W as a whole number, M must be multiple of 5

Therefore M = 5 or 10

If M = 5, W = (100-45)/5 = 11 and children = 100-5-11 =  84

If M = 10, W = (100-90)/5 = 2 and children = 100-10-2 = 88

8 0
3 years ago
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