Answer:
Part A: A(m(t)) = π(81t²); Part B: 1017.36
Step by step explanation:
Part A:
To find A(m(t)), we substitute our value for m(t), 9t, in place of m:
A(m(t)) = πm² = π(9t)² = π(81t²)
A(m(t)) = π(81t²)
Part B:
Substitute 2 in for t:
A(m(2)) = π(81(2²)) = π(81(4)) = 3.14(324) = 1017.36
Answer:
B
Step-by-step explanation:
The solution is the point of intersection, which is (-1, 3)
im pretty sure true because they do not intersect and are not parallel :)
We could use the formula, derive the formula, or just work it out for this case. Let's do the latter.
The distance of a point to a line is the length of the perpendicular from the line to the point.
So we need the perpendicular to 5x-4y=10 through (-1,3). To get the perpendicular family we swap x and y coefficients, negating one. We get the constant straightforwardly from the point we're going through:
4x + 5y = 4(-1)+5(3) = 11
Those lines meet at the foot of the perpendicular, which is what we're after.
4x + 5y = 11
5 x - 4y = 10
We eliminate y by multiplying the first by four, the second by five and adding.
16x + 20y = 44
25x - 20y = 50
41x = 94
x = 94/41
y = (11 - 4x)/5 = 15/41
We want the distance from (-1,3) to (94/41,15/41)
Answer:
6
Step-by-step explanation: