Once hundred and<br>eight<br>ht and two tens as a decimal

Brain ate 5 pieces of pie. The pie was cut into 6 equal pieces

LUCKY_DIMON [66]

Answer:

C. 5 sixths

Step-by-step explanation:

5/6 = 5 sixths

4 0

3 years ago

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For each level of precision, find the required sample size to estimate the mean starting salary for a new CPA with 95 percent co

Rzqust [24]

Answer:

(a) Margin of error ( E) = $2,000 , n = 54

(b) Margin of error ( E) = $1,000 , n = 216

(c) Margin of error ( E) = $500 , n= 864

Step-by-step explanation:

Given -

Standard deviation $\sigma$ = $7,500

$\alpha$ = 1 - confidence interval = 1 - .95 = .05

$Z_{\frac{\alpha}{2}}$ = $Z_{\frac{.05}{2}}$ = 1.96

let sample size is n

(a) Margin of error ( E) = $2,000

Margin of error ( E) = $Z_{\frac{\alpha}{2}}\frac{\sigma}{\sqrt{n}}$

E = $Z_{\frac{.05}{2}}\frac{7500}{\sqrt{n}}$

Squaring both side

$E^{2} = 1.96^{2}\times\frac{7500^{2}}{n}$

$n =\frac{1.96^{2}}{2000^{2}} \times 7500^{2}$

n = 54.0225

n = 54 ( approximately)

(b) Margin of error ( E) = $1,000

E = $Z_{\frac{\alpha}{2}}\frac{\sigma}{\sqrt{n}}$

1000 = $Z_{\frac{.05}{2}}\frac{7500}{\sqrt{n}}$

Squaring both side

$1000^{2} = 1.96^{2}\times\frac{7500^{2}}{n}$

$n =\frac{1.96^{2}}{1000^{2}} \times 7500^{2}$

n = 216

(c) Margin of error ( E) = $500

E = $Z_{\frac{\alpha}{2}}\frac{\sigma}{\sqrt{n}}$

500 = $Z_{\frac{.05}{2}}\frac{7500}{\sqrt{n}}$

Squaring both side

$500^{2} = 1.96^{2}\times\frac{7500^{2}}{n}$

$n =\frac{1.96^{2}}{500^{2}} \times 7500^{2}$

n = 864

7 0

3 years ago

Need help checking my answers thanks!!

Hitman42 [59]

Answer:

They are correct good job!

Step-by-step explanation:

3 0

2 years ago

Read 2 more answers

Use the method of least squares to solve the following problem.

slamgirl [31]

Purr fbfbfbffjhfbfbfbfbfbfbf

3 0

3 years ago

3. For the function, :c(X)=x^2+4x-5 over x+5<br> (a) Identify the restricted domain value(s).

Mrrafil [7]

Domain is all the possible inputs of an equation. In this example, the only concern is the x + 5 because the denominator cannot equal 0 because we can't divided by 0. So we set x + 5 equal to zero and solve for x.

x + 5 = 0
x = -5
The restriction is that x cannot equal -5.

8 0

3 years ago

Once hundred andeightht and two tens as a decimal ​

Once hundred andeightht and two tens as a decimal