All categories

1 year ago

Angles in circles geometry

Mathematics

1 answer:

Scrat [10]1 year ago

5 0

Answer:

inscribed angle

Step-by-step explanation:

When the vertex (point, corner) of an angle is ON the circle, the angle is an inscribed angle.

You might be interested in

ALL LGBTQ PEOPLE SAY YAS AND is this true

masha68 [24]

thats called the story of my life ahah. plus all the cute celeberties be straight like eeeeeeeeeeeeeee

3 0

2 years ago

Read 2 more answers

295 times 67 long multiplication

Fittoniya [83]

19,765 but couldnt u just use a calculator??

8 0

3 years ago

Read 2 more answers

Describe the transformation from the graph of g(x) = x+2 to the graph of g(x)=x-7

Alex

x+2 will be translated 2 units to the left horizontally from the origin
x-7 will be translated 7 units to the right horizontally from the origin

Compared to the graph of x-7 , x+2 is 9 units to the left and to x+2, x-7 is 9 units to the right.

Hope it is helpful!

Don't forget to mark as brainliest ! ;)

3 0

2 years ago

Read 2 more answers

Micah is writing a function that models the height a dolphin reaches when it propels itself from underwater to the surface, leap

stepladder [879]

Answer:

The dolphin will be above the surface of the water for 2 seconds.

Step-by-step explanation:

Solving a quadratic equation:

Given a second order polynomial expressed by the following equation:

$ax^{2} + bx + c, a\neq0$ .

This polynomial has roots $x_{1}, x_{2}$ such that $ax^{2} + bx + c = a(x - x_{1})*(x - x_{2})$ , given by the following formulas:

$x_{1} = \frac{-b + \sqrt{\Delta}}{2*a}$

$x_{2} = \frac{-b - \sqrt{\Delta}}{2*a}$

$\Delta = b^{2} - 4ac$

The height of the dolphin after t seconds is given by:

$h(t) = -16t^2 + 96t - 128$

According to Micha's model, how long will the dolphin be above the surface of the water?

It stays above the surface of the water between the first and the second root. Initially, it is below water, when the first time for which $h(t) = 0$ it crosses the surface upwards, and then the second time for which $h(t) = 0$ it crosses the surface downwards.