answer:
in order to construct 75°, you need to use a protractor and a compass
step-by-step explanation:
here is a step-by-step explanation from an online source
- step 1: draw a line segment with endpoint O and A
- step 2: draw an arc with O as centre cutting the line segment OA at point B with a compass
- step 3: keeping the radius same, draw an arc with B as centre cutting the arc at C
- step 4: keeping the radius same, and C as the center, draw an arc intersecting the arc drawn in the previous step at D
- step 5: with any radius, draw two arcs with C and D as a center. intersect these two arcs at E
- step 6: join OE. angle EOA is the angle with measurement of 90 degrees
- step 7: now the line OE intersect the arc at the point F
- step 8: taking F and C as a center, make an arc with a radius of more than half of the measurement FC. the arc intersects at point H
- step 9: join the point H and O. angle HOA is the angle obtained of measurement 75 degrees
- step 10: angle HOA is the desired angle
The formula for an arithmetic sequence is An=A1+(n-1)d.
Using this knowledge, you can set up the equation easily to be An=1+(12-1)-5
You then simplify this to 1-55 using PEMDAS, giving you the answer for the twelfth term being -54, you then do this for every term if you want (or you could just subtract 5 by the terms after 14 till you get to -54. After all that, you add the twelve terms up to get -319 as your final answer
Answer:
x ≤8/5
Step-by-step explanation:
6x - 9 ≥ 11x - 17
Subtract 6x from each side
6x -6x-9 ≥ 11x - 17-6x
-9 ≥ 5x- 17
Add 17 to each side
-9+17≥ 5x - 17+17
8≥ 5x
Divide each side by 5
8/5≥ 5x /5
8/5≥ x
Answer:
The area of the square is 85 units^2
Step-by-step explanation:
Okay, here in this question, we are interested in calculating the area of the unknown square.
Kindly note that, since each of the other shapes are squares too, it means that the length of their sides is simply the square root of their areas.
Thus, the length of the squares are ;
√35 units and √50 units respectively
Now to find the area of the larger square, we employ the use of Pythagoras’ theorem which states that the square of the hypotenuse is equal to the sum of the squares of the two other sides
Let’s call the unknown length X
x^2 = (√35)^2 + (√50)^2
x^2 = 35 + 50
x^2 = 85
x = √85 units
Now as we know that the area of a square is simply the length of the side squared,
The area of the biggest square is simply (√85)^2 = 85 units^2
