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SpyIntel [72]
3 years ago
9

How can you represent division of fractions

Mathematics
1 answer:
grin007 [14]3 years ago
8 0

Hope it helps yah ... (・∀・)

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Use scientific notation to estimate the number of inches in 1,225 miles
madam [21]
First, find the number of inches
<span>1225 Miles = 77616000 Inches

then, move the decimal to until you have a ones place.    </span>
<span>77616000.    the decimal for this number moves to the left SEVEN places.
you end up with 7.7616000
</span>
it will look like this:

7.8 * 10^7

I rounded to the .8 because you didn't state how many significant figures, but it could easily be 7.76 * 10^7

the exponent above the 10 will tell you how many places to move. to get back to your original number, move it back to the right seven places. Of course, you would have to place hold the numbers with 0s. If it were negative, you would move the decimal the opposite way.
6 0
3 years ago
Which equation has a constant of proportionality equal to 0.25
laila [671]

Answer: y = 1/4x

Step-by-step explanation:

If the constant of proportionality is K, then:

y = kr

In which equation do we multiply x by 0.25 to get y?

1/4 = 0.25

5 0
3 years ago
PLEASE HELP . ILL MAKE BRAINLIEST !! PLEASE
asambeis [7]

Answer:

62

Step-by-step explanation:

add

and then mutupy them together

8 0
3 years ago
Need help with my homework ​
Volgvan

Answer:

\displaystyle y=\frac{16-9x^3}{2x^3 - 3}

\displaystyle y=-\frac{56}{13}

Step-by-step explanation:

<u>Equation Solving</u>

We are given the equation:

\displaystyle x=\sqrt[3]{\frac{3y+16}{2y+9}}

i)

To make y as a subject, we need to isolate y, that is, leaving it alone in the left side of the equation, and an expression with no y's to the right side.

We have to make it in steps like follows.

Cube both sides:

\displaystyle x^3=\left(\sqrt[3]{\frac{3y+16}{2y+9}}\right)^3

Simplify the radical with the cube:

\displaystyle x^3=\frac{3y+16}{2y+9}

Multiply by 2y+9

\displaystyle x^3(2y+9)=\frac{3y+16}{2y+9}(2y+9)

Simplify:

\displaystyle x^3(2y+9)=3y+16

Operate the parentheses:

\displaystyle x^3(2y)+x^3(9)=3y+16

\displaystyle 2x^3y+9x^3=3y+16

Subtract 3y and 9x^3:

\displaystyle 2x^3y - 3y=16-9x^3

Factor y out of the left side:

\displaystyle y(2x^3 - 3)=16-9x^3

Divide by 2x^3 - 3:

\mathbf{\displaystyle y=\frac{16-9x^3}{2x^3 - 3}}

ii) To find y when x=2, substitute:

\displaystyle y=\frac{16-9\cdot 2^3}{2\cdot 2^3 - 3}

\displaystyle y=\frac{16-9\cdot 8}{2\cdot 8 - 3}

\displaystyle y=\frac{16-72}{16- 3}

\displaystyle y=\frac{-56}{13}

\mathbf{\displaystyle y=-\frac{56}{13}}

8 0
3 years ago
W + 4 = 16<br> Need for a test
Nady [450]

Answer:

12

Step-by-step explanation:

when + go to the other side it has to be -

w=16-4

=12

7 0
3 years ago
Read 2 more answers
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