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SpyIntel [72]
3 years ago
9

How can you represent division of fractions

Mathematics
1 answer:
grin007 [14]3 years ago
8 0

Hope it helps yah ... (・∀・)

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The Venn diagram shows the results of two events resulting from rolling a number cube.
lorasvet [3.4K]

Answer:

Option B.

Step-by-step explanation:

From the given venn diagram it is clear that

A={1,2}

B={1,2,3,4,5,6}

A\cap B={1,2}

Since the intersection of A and B is non-empty, therefore by conditional probability

P(B|A)=\dfrac{P(A\cap B)}{P(A)}

P(B|A)\cdot P(A)=P(A\cap B)

P(A\cap B)=P(B|A)\cdot P(A)

Therefore, the correct option is B.

8 0
3 years ago
Gabe went to the amusement park with $40 to spend. His ticket cost $26.50. Write and solve an inequality to show how much he mig
Goshia [24]
<h3><u>An inequality to show how much he might spend on souvenirs and snacks is:</u></h3>

x\leq 13.5

<h3><u>Solution:</u></h3>

Given that,

Gabe went to the amusement park with $40 to spend

His ticket cost $26.50

Therefore,

Total amount she has = $ 40

Ticket cost = $ 26.50

Let "x" be the amount he might spend on souvenirs and snacks

Therefore,

Remaining amount = 40 - 26.50

Remaining amount = 13.5

Thus she can spend less than or equal to $ 13.5 on souvenirs and snacks

Which is represented in inequality as:

x\leq 13.5

Thus the inequality is found

4 0
3 years ago
Help please!!!!
MissTica

Answer:

I'm not sure about it

Step-by-step explanation:

4 0
3 years ago
Chose the equivelent expression for the scenario. phillip mows lawns fro $15 each. if he moves 6 lawn every week for 8 weeks. ho
Ipatiy [6.2K]

Answer:

15 x 6 x 8

Step-by-step explanation:

total money is cost per lawn times number of lawns per week times number of weeks

cost per lawn is $15

number of lawns per week is 6

number of weeks is 8

so cost total money is 15 x 6 x 8 which is none of them

where did the 20 and 11 come from?

3 0
3 years ago
Rewrite the following in the form log(c). log(4) - log(2)
Elis [28]

Answer:

log(2)

Step-by-step explanation:

log(4) − log(2)

log(4/2)

log(2)

3 0
3 years ago
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