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prohojiy [21]
1 year ago
10

What is the asymptote of the graph of f(x)=5x−1?

Mathematics
1 answer:
Marina86 [1]1 year ago
3 0

The asymptotes of the graph of f(x) = \frac{5}{x - 1} are as follows:

  • Vertical: x = 1.
  • Horizontal: y = 0.

<h3>What are the asymptotes of a function f(x)?</h3>

  • The vertical asymptotes are the values of x which are outside the domain, which in a fraction are the zeroes of the denominator.
  • The horizontal asymptote is the value of f(x) as x goes to infinity, as long as this value is different of infinity.

In this problem, the function is:

f(x) = \frac{5}{x - 1}

For the vertical asymptote, we have that:

x - 1 = 0 \rightarrow x = 1.

For the horizontal asymptote, we have that:

y = \lim_{x \rightarrow \infty} f(x) = \frac{5}{\infty - 1} = 0.

More can be learned about asymptotes at brainly.com/question/16948935

#SPJ1

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What is the image of N for a 300° counterclockwise rotation about the center of the regular hexagon? Will give brainiest only if
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Answer:

H

Step-by-step explanation:

here, the question says that the given regular hexagon needs to be rotated counter clockwise 300°, considering the edges labels, each movement from one edge to other is 60° as 360/6 =60.

focus on N and move on anti clockwise.

When N rotates anti clockwise about center from original to position G, is 60°,

when N moves on anti clockwise about center from original to position A is 120°.

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How would you write the absolute value of 5.23
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3 years ago
Find the length of the diagonal of a square with perimeter of 24
julsineya [31]

Answer:

d = 6sqrt(2) or 8.4853

Step-by-step explanation:

<u><em>Formula</em></u>

P = 4*s

s^2 + s^2 = d^2 where d is the diagonal and s is the side.

<u><em>Givens</em></u>

P = 24

<u><em>Solution</em></u>

P = 4s         Substitute for s

24 = 4*s      Divide by 4

24/4 = s

s = 6

================

d^2 = s^2 + s^2

d^2 = 6^2 + 6^2

d^2 = 36 + 26

d^2 = 72

d = sqrt(72)

Factors of 72

72: 6 * 6 * 2

<em><u>Rule</u></em>: Every pair of = factors allows you to take one of them outside the sqrt sign and throw the other a way. If there are no pairs, whatever you started with stays under the root sign.

sqrt(6*6*2) = 6sqrt(2)

  • The diagonal length is either
  • d = 6*sqrt(2) or
  • d = 8.4853

8 0
3 years ago
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