one would say that the simple interest doubles if the period of time is specified in the contract and the contract is still valid, if the interest amount is available anitime and so on.
So if the amount doubles let's say at half time for which the principal was awarded to the bank, by the end of the contract , the interest amount can be double × just increased by 1.5
Answer:
C. 434π
Step-by-step explanation:
Given:
Radius (r) = 7 in.
Height (h) = 24 in.
Required:
Surface area of the cylinder
Solution:
S.A = 2πrh + 2πr²
Plug in the values
S.A = 2*π*7*24 + 2*π*7²
S.A = 336π + 98π
S.A = 434π
6x+3-(8x-5)
=
-2x(x-4)
=
2x+8
=
p = 2
Answer:
y = 1
Step-by-step explanation:
Passes through (6,-1)(6,-1)
Find the slope (m)
m=(y2 - y1) / (x2 - x1)
m=(-1 - (-1) ) / (6-6)
m= 0
Parallel to x - 3y = 3
-3y = -x +3
y = 1/3 x -1
Equation of the line equation is y - y1 = m ( x - x1 )
y - ( -1 ) = 0 ( x - 6 )
y + 1 = 0
y = 1
Answer:
Y = 28.31
Z = 13.29
Angle A = 28
Step-by-step explanation:
For Angle A:
Remember a triangle has a total of 180 degree angles. So set up your formula as
180 - 62 -90 = Angle A
For Y:
The sine of an angle is equal to the ratio of the opposite side to the hypotenuse.
sin (B) = opp/hyp or b/c or (y)
sinB = 62
b = 25
Rewrite as c=b/2SinB -> c=25/sin62 -> Y = 28.31
For Z:
Use the Pythagorean theorem to find the unknown side.

z = 13.29