For this case we have the following function:

By the time the stone is thrown, x = 0.
We must evaluate this value of x in the function.
We have then:
Answer:
The height of the stone at the time is thrown is given by:
h (0) = 15 meters
All you have to do is put 36/125. This will get you .288. When rounded to the nearest percent, it is 28%.
Step-by-step answer:
Given:
mean, mu = 200 m
standard deviation, sigma = 30 m
sample size, N = 5
Maximum deviation for no damage, D = 100 m
Solution:
Z-score for maximum deviation
= (D-mu)/sigma
= (100-200)/30
= -10/3
From normal distribution tables, the probability of right tail with
Z= - 10/3
is 0.9995709, which represents the probability that the parachute will open at 100m or more.
Thus, by the multiplication rule, the probability that all five parachutes will ALL open at 100m or more is the product of the individual probabilities, i.e.
P(all five safe) = 0.9995709^5 = 0.9978565
So there is an approximately 1-0.9978565 = 0.214% probability that at least one of the five parachutes will open below 100m
The gcf of the numbers are 15
Answer:
Step-by-step explanation:
What I would do is convert everything to have a denominator of 10 so it could be easier to add.
6 would equal 60/10
7 would equal 70/10
2/5 would equal 4/10
now add all together
60/10 + 70/10 + 4/10 +9/10 and you get 143/10. If you wanted to simplify you would get 14 3/10 or 14.30