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Tamiku [17]
3 years ago
12

[tex]2yx^{4} x 5yx^{3}

Mathematics
1 answer:
Paladinen [302]3 years ago
4 0

Answer:B

Step-by-step explanation: hopes this helps

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For which equations are in the solution for x the same number? 15 – х = -3<br> 3
Norma-Jean [14]

Answer:

Step-by-step explanation:

First equation:

          15 - x = - 3

           -x = - 3 - 15

          -x  =  -18  (now negative signs on b.s cut eachother)

            [x  =  18]

Second equation :

         15 - x = 3

          -x = 3 - 15

          - x = -12 ( now negative sign on b.s cut eachother)

            [x = 12]

so x = 18 and x = 12 are not same

6 0
3 years ago
Which is another way to write 6-(-7)=13
marshall27 [118]

6+7=13 is the another way to write ...

hope it is helpful.Thankyou!!!!

7 0
3 years ago
The equation of a circle is shown below. What is its center and radius? (x - 5.3)^2 + (y + 3.3)^2=49. ANSWERS ATTACHED, 15 POINT
sweet [91]

Answer:

The center is ( 5.3, -3.3) and 7 is the radius

Step-by-step explanation:

We can write the equation of a circle as

( x-h)^2 + ( y-k)^2 = r^2

Where ( h,k) is the center and r is the radius

(x - 5.3)^2 + (y + 3.3)^2=49

(x - 5.3)^2 + (y -  -3.3)^2=7^2

The center is ( 5.3, -3.3) and 7 is the radius

8 0
3 years ago
Which expression is equivalent to 2⁵
Misha Larkins [42]

Answer:

2*2*2*2*2

Step-by-step explanation:

You just multiply 2 five times.

7 0
3 years ago
Usha thinks that the area of the development will be greater than the total area of 50 football pitches.
tangare [24]

Answer:

Usha is correct

Step-by-step explanation:

See attachment

Given

Dimension of the development

Height = \frac{1}{2}\ mile

Base = \frac{1}{2}\ mile

Dimension of a football field

Length = 100m

Width = 50m

First, we calculate the area of the development.

Because it is triangular in shape, the area is:

Area = \frac{1}{2} * Height * Base

Area = \frac{1}{2} * \frac{1}{2}mile * \frac{1}{2}mile

Convert mile to meter

Area = \frac{1}{2} * \frac{1}{2}* 1600m * \frac{1}{2} * 1600m

Area = \frac{1}{2} * 800m * 800m

Area = 400m * 800m

Area = 320000m^2

The area of 50 football pitch is then calculated as:

Area = 50 * Length * Width

Area = 50 * 100m * 50m

Area = 250000m^2

By comparison:

320000 > 250000

<em>Hence, Usha's thought is correct</em>

5 0
3 years ago
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