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malfutka [58]
1 year ago
10

Solve this equation 3x - 5 = -26​

Mathematics
2 answers:
Dmitry_Shevchenko [17]1 year ago
5 0

3x - 5 = -26​

<u>step 1:</u>

subtract +5 on each side because you have to do the inverse operation

<u>step 2:</u>

3x= -21

<u>step 3:</u>

now divide 3 on each side

the answer is -7

<u />

Hope this helped!

<u />

<em>TheOneAndOnlyLara~</em>

Alja [10]1 year ago
5 0

Answer:

x=-7.

Step-by-step explanation:

Hi student! Let me help you out.

_________________

First, add 5 to both sides.

\sf 3x=-26+5. Upon simplifying, we obtain this.

\sf 3x=-21.

                                          <em>  ↪</em>

Now divide both sides, by 3.

\sf x=-7

\therefore,\sf the \quad value \quad of \quad x \quad is \quad -7. Which is our final answer.

⇨Hope that this helped! have a great day ahead! ⇦

Best Wishes!

\star\bigstar\underline{\overline{\overline{\textsf{Reach far. Aim high. Dream big.}}}}

<em>◆◆-Greetings!-◈◈</em>

__________________________

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A random sample of size n1= 25, taken from a normal population with a standard deviation σ1= 5, has a mean X1= 80. A second rand
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Answer:

The 94% confidence interval would be given by 2.898 \leq \mu_1 -\mu_2 \leq 7.102

Step-by-step explanation:

Previous concepts  

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

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\bar X_1 =80 represent the sample mean 1

\bar X_2 =75 represent the sample mean 2

n1=25 represent the sample 1 size  

n2=36 represent the sample 2 size  

\sigma_1 =5 sample standard deviation for sample 1

\sigma_2 =3 sample standard deviation for sample 2

\mu_1 -\mu_2 parameter of interest.

The confidence interval for the difference of means is given by the following formula:  

(\bar X_1 -\bar X_2) \pm z_{\alpha/2}\sqrt{\frac{\sigma^2_1}{n_1}+\frac{\sigma^2_2}{n_2}} (1)  

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\bar X_1 -\bar X_2 =80-75=5

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The standard error is given by the following formula:

SE=\sqrt{\frac{\sigma^2_1}{n_1}+\frac{\sigma^2_2}{n_2}}

And replacing we have:

SE=\sqrt{\frac{5^2}{25}+\frac{3^2}{36}}=1.118

Confidence interval

Now we have everything in order to replace into formula (1):  

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So on this case the 94% confidence interval would be given by 2.898 \leq \mu_1 -\mu_2 \leq 7.102  

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