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kodGreya [7K]
2 years ago
13

Below is the graph of a trigonometric function. It intersects its midline at (3.7, 5) and again at (5.9, 5).

Mathematics
1 answer:
Flauer [41]2 years ago
8 0

Answer:

4.4

Step-by-step explanation:

The parent function of this graph is:  y = sin(x)

The sine function is periodic, meaning it repeats forever.

Standard form of a sine function:

\sf f(x)= A \sin(B(x+C))+D

where:

  • A = amplitude (height from the mid-line to the peak)
  • 2π/B = period (horizontal distance between consecutive peaks)
  • C = phase shift (horizontal shift - positive is to the left)
  • D = vertical shift

The <u>period</u> is the horizontal distance between consecutive peaks, which is the same as <u>twice the horizontal distance between the intersection of the curve and the mid-line</u>.

Given consecutive points of intersection between the curve and the mid-line:

  • (3.7, 5)
  • (5.9, 5)

Therefore, the horizontal distance between these two points is:

5.9 - 3.7 = 2.2

⇒ Period = 2.2 × 2 = 4.4

-------------------------------------------------------------------------------------

To create the equation for the function.

From inspection of the given graph:

  • Amplitude (A) = 6
  • Mid-line is y = 5
  • Vertical shift (D) = +5

Period = 2π/B = 4.4  ⇒  B = 5π/11

Phase Shift (C) = -3.7

Substituting the values into the standard form:

\implies \sf f(x)= 6 \sin\left(\dfrac{5}{11}\pi(x-3.7)\right)+5

\implies \sf f(x)= 6 \sin\left(\dfrac{5}{11} \pi x-\dfrac{37}{22}\pi \right)+5

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Answer:

\large \boxed{y =  -  \frac{1}{9} x -  \frac{5}{9} }

Step-by-step explanation:

In order to find an equation of a line with two given ordered pairs. We have to find a slope first which we can do by using the formula below.

\large \boxed{m =  \frac{y_2 - y_1}{x_2 - x_1} }

m-term is defined as slope in y = mx+b form which is slope-intercept form.

Now we substitute these ordered pairs (x, y) in the formula.

\large{m =  \frac{1 - ( - 2)}{ -14 - 13} } \\  \large{m =  \frac{1 + 2}{ - 27} } \\  \large{m =  \frac{3}{ - 27}  =  -  \frac{1}{9} }

After we calculate for slope, we substitute m-value in slope-intercept form. The slope-intercept form is

\large \boxed{y = mx + b}

We already know m-value as we substitute it.

\large{y =  -  \frac{1}{9} x  + b}

We are not done yet because we need to find the b-term which is our y-intercept. (Note that m-term is slope while b-term is y-intercept)

We can find the y-intercept by substituting either (-14,1) or (13,-2) in the equation. I will be using (13,-2) to substitute in the equation.

\large{y = -  \frac{1}{9} x + b} \\  \large{ - 2 =  -  \frac{1}{9} (13) + b} \\  \large{ - 2 =  -  \frac{13}{9}  + b} \\  \large{ - 2 +  \frac{13}{9}  = b} \\  \large{ -  \frac{5}{9}  = b}

Finally, we know b-value. Then we substitute it in our equation.

\large{y =  -  \frac{1}{9} x + b} \\  \large{y =  -  \frac{1}{9} x -  \frac{5}{9} }

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