2/3y-2/5=5
We move all terms to the left:
2/3y-2/5-(5)=0
Domain of the equation: 3y!=0
y!=0/3
y!=0
y∈R
determiningTheFunctionDomain
2/3y-5-2/5=0
We calculate fractions
There is no solution for this equation
Answer:
yysududufududydhxududurfuuru
udududurudud
Answer:
Naw I can't help ya I gotta find my notes
To find invers
1. solve for y
2. replace y with xinverse
so
x=4-4y+y^2
reorder right side
x=y^2-4y+4
factor right side
x=(y-2)^2
squaer root both sides
+/-√x=y-2
add 2 to both sides
2+/-√x=y
switch x and y
2+/-√y=xinverse
xinverse=2+√y or 2-√y
subtract 4 from both sides
I believe the answer is A.
The other values have repeated X values.