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Alex73 [517]
3 years ago
9

Tarzan (75 kg) swings from 4 metres high on a vine down to ground level and catches Jane (50 kg). How fast are they moving after

he cares her?
Physics
1 answer:
Kruka [31]3 years ago
5 0

Try this solution (if it is possible, check it in other sources):

1. for m_Tarzan=75kg., initial_height=4m., end_height=0 m. and g=10 N/kg. Energy is:

E=m_{Tarzan}*(H_{initial}-H_{end})*g=75*4*10=3000(J).

2. The same value of Energy is applied for m_Tarzan+Jane=75+50=125 kg.:

E=\frac{m_{Tarzan+Jane}* Speed^2}{2}; \ => \ Speed=\sqrt{ \frac{2*E}{m_{Tarzan+Jane}}};

3. According to the formula of the Speed:

Speed=sqrt(6000/125)=sqrt(48)=4sqrt(3)≈4*1.71=6.84 (m/s)


Answer: 6.84 (m. per sec.)

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Answer:

The height of the tree is three (3) deep

Explanation:

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This is illustrated below.

129

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Question 7 (3 points)
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Therefore, what you attempted to demonstrate with the electric motor, is how you can convert electrical energy to mechanical energy

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