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Digiron [165]
3 years ago
15

Where is the most of the liquid freshwater on earth located?

Physics
2 answers:
amm18123 years ago
7 0

c) Oceans

hope this helps!

iren2701 [21]3 years ago
6 0

Not sure but i will say D

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A disk with radius R and uniform positive charge density s lies horizontally on a tabletop. A small plastic sphere with mass M a
Yanka [14]

Answer:

a. F = Qs/2ε₀[1 - z/√(z² + R²)] b.  h =  (1 - 2mgε₀/Qs)R/√[1 - (1 - 2mgε₀/Qs)²]

Explanation:

a. What is the magnitude of the net upward force on the sphere as a function of the height z above the disk?

The electric field due to a charged disk with surface charge density s and radius R at a distance z above the center of the disk is given by

E = s/2ε₀[1 - z/√(z² + R²)]

So, the net force on the small plastic sphere of mass M and charge Q is

F = QE

F = Qs/2ε₀[1 - z/√(z² + R²)]

b. At what height h does the sphere hover?

The sphere hovers at height z = h when the electric force equals the weight of the sphere.

So, F = mg

Qs/2ε₀[1 - z/√(z² + R²)] = mg

when z = h, we have

Qs/2ε₀[1 - h/√(h² + R²)] = mg

[1 - h/√(h² + R²)] = 2mgε₀/Qs

h/√(h² + R²) = 1 - 2mgε₀/Qs

squaring both sides, we have

[h/√(h² + R²)]² = (1 - 2mgε₀/Qs)²

h²/(h² + R²) = (1 - 2mgε₀/Qs)²

cross-multiplying, we have

h² = (1 - 2mgε₀/Qs)²(h² + R²)

expanding the bracket, we have

h² = (1 - 2mgε₀/Qs)²h² + (1 - 2mgε₀/Qs)²R²

collecting like terms, we have

h² - (1 - 2mgε₀/Qs)²h² = (1 - 2mgε₀/Qs)²R²

Factorizing, we have

[1 - (1 - 2mgε₀/Qs)²]h² = (1 - 2mgε₀/Qs)²R²

So, h² =  (1 - 2mgε₀/Qs)²R²/[1 - (1 - 2mgε₀/Qs)²]

taking square-root of both sides, we have

√h² =  √[(1 - 2mgε₀/Qs)²R²/[1 - (1 - 2mgε₀/Qs)²]]

h =  (1 - 2mgε₀/Qs)R/√[1 - (1 - 2mgε₀/Qs)²]

4 0
3 years ago
If the mess of an object______, the weight of an object will _______
Gnom [1K]

Answer:

the same

Explanation:

7 0
3 years ago
I'm not sure what equation to use.
Lelechka [254]
I would think that you would multiply then divide
7 0
4 years ago
Ground-based radio telescopes can collect data from distant objects in space
Arada [10]
Answer is A. Because the telescope are use in night
4 0
3 years ago
Read 2 more answers
g A 45.0 - kg girl is standing on a 150. - kg plank. The plank, originally at rest, is free to slide on a frozen lake, which is
oksian1 [2.3K]

Answer:

velocity of girl with respect  to surface of ice 1.154 m/s

Explanation:

Plank Mass , M = 150 kg

Girl Mass , m = 45 kg

velocity of the girl with resect to plank, v1 = 1.50 m/s

velocity of the plank + girl = v2

from the conservation of momentum

Momentum (plank+girl) = - momentum of the girl

(M+m)v2 = -mv1

v2 = -(45 kg)/(195 kg) * 1.50

v2 = -0.346 m/s

velocity of girl with respect  to surface of ice =

  v1+v2 = 1.50 + (-0.346) = 1.154 m/s

4 0
3 years ago
Read 2 more answers
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