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Burka [1]
2 years ago
10

Find the next 3 terms of the following sequences a.4,9, 16,25 b.1,4,9, 16 c.1,4,7,10 d.3,9, 15, 21​

Mathematics
2 answers:
evablogger [386]2 years ago
8 0

Answer:

for a) the next three would be 36, 49 and 64

for b) the next three would be 25, 36 and 49

for c) the next three would be 13, 16, and 19

for d) the next three would be 27, 33, and 39

Step-by-step explanation:

Sati [7]2 years ago
6 0

Answers:

  • (a) 36, 49, 64
  • (b) 25, 36, 49
  • (c) 13, 16, 19
  • (d) 27, 33, 39

========================================================

Explanations:

  • (a) The given terms 4,9,16,25 are perfect squares (eg: 16 = 4^2 and 5^2 = 25). The next set of perfect squares are 6^2 = 36, 7^2 = 49 and 8^2 = 64.
  • (b) Similar to the previous part. This time the next three terms are 25, 36, and 49 because 5^2 = 25, 6^2 = 36 and 7^2 = 49.
  • (c) We start at 1 and add 3 each time. This sequence is arithmetic. The next term after 10 is 10+3 = 13. After that is 13+3 = 16. Finally 16+3 = 19 is the last term we need.
  • (d) Similar to part (c) earlier. This time we start at 3 and add 6 each time. The next three terms are 21+6 = 27, and 27+6 = 33, and finally 33+6 = 39
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galben [10]
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4 0
3 years ago
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Evaluate 4!.<br><br> a.) 4<br> b.) 12<br> c.) 24
Gwar [14]

Answer

24


Explanation

4! This is read as 4 factorial.


It means;

4! = 4×3×2×1

= 24

6 0
3 years ago
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STALIN [3.7K]
-8/27

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2 years ago
How does the closure property relate to polynomials?<br> Open answer question (please hurry)
Marianna [84]

Answer:

Polynomials will be closed under an operation if the operation produces another polynomial. When adding polynomials, the variables and their exponents do not change. ... When subtracting polynomials, the variables and their exponents do not change. Only their coefficients will possibly change.

Step-by-step explanation:

3 0
3 years ago
I need help!! #28 #29<br> Please!!!!!
Marta_Voda [28]

Answer:

Step-by-step explanation:

We would apply the formula for binomial distribution. It is expressed as

P(x = r) = nCr × q^(n - r) × p^r

Where

n = number of samples

p = probability of success.

q = probability of failure

From the information given,

n = 12

p = 90% = 90/100 = 0.9

q = 1 - p = 1 - 0.9 = 0.1

28) Probability that at least 10 are ripe within 4 days is expressed as

P(x ≥ 10) = P(x = 10) + P(x = 11) + P(x = 12)

P(x = 10) = 12C10 × 0.1^(12 - 10) × 0.9^10 = 0.23

P(x = 11) = 12C11 × 0.1^(12 - 11) × 0.9^11 = 0.38

P(x = 12) = 12C12 × 0.1^(12 - 12) × 0.9^12 = 0.28

P(x ≥ 10) = 0.23 + 0.38 + 0.28 = 0.89

29) Probability that no more than 9 are ripe within 4 days is expressed as

P(x ≤ 9) = 1 - P(x ≥ 10)

P(x ≤ 9) = 1 - 0.89 = 0.11

4 0
3 years ago
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