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oee [108]
3 years ago
8

What is the value of x? Round your answer to the nearest tenth if necessary.

Mathematics
1 answer:
Bezzdna [24]3 years ago
7 0
Using pythagoras theorem,
x= \sqrt{ 17^{2} - 6^{2} }  \\ = \sqrt{289-36}  \\ = \sqrt{253}  \\ =15.9
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What is the value of a in the equation 3a+b=54, when b=9?
insens350 [35]

3a+9=54

3a+9-9=54-9

3a= 45

a=15

Check answer:

3(15)+9=54

54=54

Answer is a=15

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How to construct pie charts
KengaRu [80]

Answer:


Step-by-step explanation:

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5 0
3 years ago
PLEASEEEE HELP IW ILL GIVE BRAINLIest
Temka [501]

Answer:

t1= 2-3-6=-7

t2=8-6-6=-4

t3= 18-9-6=3

3 0
2 years ago
Find the center and the radius of the circle with the equation x^2-4x+y^2-12y+31=0
ivanzaharov [21]
<h2>C: Center: (2, 6)</h2><h2>Radius: 3</h2>

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5 0
3 years ago
IGIVEEEEEEEEEEEEEEEEE BRAINLILSTTT
Temka [501]

Answer:

first box (x): 10

second box (y): 12

Step-by-step explanation:

HIJ is a translation of HIJ

translation just means you move the whole thing without any rotations dialations ect just moving it

from the blue shape it is asking what do you have to do to the x and y to get to the purple shape

you have to go +_x and take away _y

when you add a digit to x it moves to the right

when you add a digit to y it goes one up

because the HIJ are equaly spaced it dosnt matter which one we choose cause it will have the same answer

im going to use J

on the blue J you can see the x value is -8

the purple J's value is 5

to get from -5 to 5 you add 10

-5+5=0

0+5=5

5+5=10

therefore the first box (x) is 10

same thing for the y value im going to use J again

blue y value of J is 7

purple y value of J is -5

their distance is 12

7-7=0

0-5=-5

7+5=12

second box (y) is 12

i hope this helps

8 0
2 years ago
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