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ioda
2 years ago
5

Find the first term and common ratio for the geometric sequence a2=-15 a4=-375

Mathematics
1 answer:
DedPeter [7]2 years ago
3 0

The first term and common ratio for the geometric sequence are -3 and 5 respectively

<h3>Geometric sequence</h3>

This are sequence that increases exponentially. The nth term of the sequence is given as:

Tn = ar^n-1

where;

a is the first term

r is the common ratio

n is the number of terms

ar = -15

ar^3 = -375

Divide

r^2 = 375/15

r^2 = 25

r = 5

Determine the first term

a= -15/r

a = -15/5

a = -3

Hence the first term and common ratio for the geometric sequence are -3 and 5 respectively

Learn more on sequence here: brainly.com/question/6561461

#SPJ1

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A LINE PASSES THROUGH THE POINTS. what is the EQUATION OF THE LINE? (2,-4) and (6,10)?
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Hey there! :)

Answer:

y = 7/2x - 11

Step-by-step explanation:

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m = \frac{\text{rise}}{\text{run}} = \frac{y_2 - y_1}{x_2 - x_1}

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m = \frac{10-(-4)}{6-2}

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3 years ago
Joline is solving the equation 0 = x2 – 5x – 4 using the quadratic formula. Which value is the negative real number solution to
Tomtit [17]

Answer:

-5.7

Step-by-step explanation:

OUR EQUATION IS A QUADRATIC EQUATION

Let Δ be our dicriminant :

  • a= 1
  • b= 5
  • c= -4
  • Δ= 5²-4*1*(-4) =25 +16 =41≥0
  • so we have two solutions x and y
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Artemon [7]
My first answer.  Lots of parts for five minutes. Took me that long to decode the question.  It looks like your multiplying where you're taking roots.


(\sqrt[4]{7})^5 = (7^{\frac 1 4})^5 = 7^{\frac 5 4}&#10;

<span>Choice A.  Next
</span>
(3^{2/3})^{1/6} = 3^{ \frac 2 3 \times \frac 1 6 } = 3^{\frac 1 9} = \sqrt[9]{ 3} &#10;&#10;&#10;

Choice B. 

\dfrac {2^{3/4} } {2 ^{1/2} }  = 2^{3/4 - 1/2} = 2^{1/4} = \sqrt[4] {2}&#10;


Choice C






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4 years ago
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