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algol [13]
2 years ago
14

[80 points] Fill in the missing word.

Computers and Technology
1 answer:
AVprozaik [17]2 years ago
8 0

Answer:

except

you can use github copilot for this  question

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What group actively creates technology recommendation for the web?
xxMikexx [17]

The NETP provides actionable recommendations to implement technology and conduct research and development successfully that can advance the effective use of technology to support learning and teaching.


Hope this helps :)



6 0
3 years ago
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Name four reasons for keeping your money in a financial institution.
nevsk [136]
1) safety
2) you can collect interest
3) helps you save your money instead of just spending all the time
4) you can gain exponential growth which then can contribute to you.gaining more retirement money when u get older
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What is the topic of the e-mail? what is the purpose of the e-mail?
const2013 [10]

Answer:

What email are you talking about?

7 0
2 years ago
Write a program that reads in an integer value for n and then sums the integers from n to 2 * n if n is nonnegative, or from 2 *
devlian [24]

Answer:

Following are the program in c++

First code when using for loop

#include<iostream> // header file  

using namespace std; // namespace

int main() // main method

{

int n, i, sum1 = 0; // variable declaration

cout<<"Enter the number: "; // taking the value of n  

cin>>n;

if(n > 0) // check if n is nonnegative

{

for(i=n; i<=(2*n); i++)

{

sum1+= i;

}

}

else //  check if n  is negative

{

for(i=(2*n); i<=n; i++)

{

sum1+= i;

}

}

cout<<"The sum is:"<<sum1;

return 0;

Output

Enter the number: 1

The sum is:3

second code when using while loop

#include<iostream> // header file  

using namespace std; // namespace

int main() // main method

{

int n, i, sum1 = 0; // variable declaration

cout<<"Enter the number: "; // taking the value of n  

cin>>n;

if(n > 0) // check if n is nonnegative

{

int i=n;  

while(i<=(2*n))

{

sum1+= i;

i++;

}

}

else //  check if n  is negative

{

int i=n;  

while(i<=(2*n))

{

sum1+= i;

i++;

}

}

cout<<"The sum is:"<<sum1;

return 0;

}

Output

Enter the number: 1

The sum is:3

Explanation:

Here we making 2 program by using different loops but using same logic

Taking a user input in "n" variable.

if n is nonnegative then we iterate the loops  n to 2 * n and storing the sum in "sum1" variable.

Otherwise iterate a loop  2 * n to n and storing the sum in "sum1" variable.  Finally display  sum1 variable .

4 0
3 years ago
Jennifer has written a short story for children. What should be her last step before she submits the story for publication? A) p
erik [133]
It would be a or c when she is writing a childerns story
5 0
4 years ago
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