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Natasha_Volkova [10]
3 years ago
6

What is the name of the port that you plug an ethernet network cable into?

Computers and Technology
1 answer:
IrinaVladis [17]3 years ago
3 0

the answer is RJ-45

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nadya68 [22]

Answer:

true

Explanation:

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9.1.3: Printing vector elements with a for loop. Write a for loop to print all NUM_VALS elements of vector courseGrades, followi
svlad2 [7]

Answer:

The program to this question as follows:

Program:

#include <iostream> //defining header file

#include <vector> //defining header file

using namespace std;

int main() //defining main method

{

//defining integer variable NUM_VALS and i.    

int NUM_VALS = 4,i;//assign value in NUM_VALS variable

vector<int> courseGrades(NUM_VALS); //defining vector array

cout<<"Input values: "; //print message

for(i=0;i<NUM_VALS;i++) //loop for input value

{

//input value in verctor array    

cin>>courseGrades[i]; //input from user-end

}

for (i = 0; i < NUM_VALS; i++) //loop to print value

{

cout<<courseGrades[i]<< " ";//print value

}

cout << endl;//for new line

for (i = NUM_VALS-1;i >= 0;i--)//loop to print value in reverse order

{

//print value in reverse order

cout << courseGrades[i] << " "; //print value

}

cout << endl; //for new line

return 0;

}

Output:

Input values: 2

3

5

6

2 3 5 6  

6 5 3 2  

Explanation:

In the above-given code two integer variable "NUM_VALS and i" is declared, in which variable "NUM_VALS" assigns a value, that is 4, in the next step, a vector array "courseGrades" is defined, in which we take input from the user end.

  • In the next step two for loop is declared, in the first loop we simply print the value of the "courseGrades".
  • The second loop is also used to print the "courseGrades" value but, in the reverse order.
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Programming CRe-type the code and fix any errors. The code should convert non-positive numbers to 1.
LUCKY_DIMON [66]

Answer:

Given

The above lines of code

Required

Rearrange.

The code is re-arrange d as follows;.

#include<iostream>

int main()

{

int userNum;

scanf("%d", &userNum);

if (userNum > 0)

{

printf("Positive.\n");

}

else

{

printf("Non-positive, converting to 1.\n");

userNum = 1;

printf("Final: %d\n", userNum);

}

return 0;

}

When rearranging lines of codes. one has to be mindful of the programming language, the syntax of the language and control structures in the code;

One should take note of the variable declarations and usage

See attachment for .cpp file

Download cpp
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