Answer:
The hypotenuse to the nearest tenth is 8.1
Step-by-step explanation:
We can use the Pythagorean theorem to solve
a^2 + b^2 = c^2 where a and b are the legs and c is the hypotenuse
Let a be the x leg and b be the y leg
a = 7 units
b= 4 units
7^2 + 4^2 = c^2
49+ 16 = c^2
65 = c^2
Take the square root of each side
sqrt(65) = sqrt(c^2)
8.062257748 =c
To the nearest tenth
8.1 =c
Answer:
hope that help for you.....
hello
the question here is
![3\sqrt[]{7}(14-4\sqrt[]{56})](https://tex.z-dn.net/?f=3%5Csqrt%5B%5D%7B7%7D%2814-4%5Csqrt%5B%5D%7B56%7D%29)
step 1
multiply through the bracket by the coeffiecient
![\begin{gathered} 3\sqrt[]{7}(14-4\sqrt[]{56}) \\ (3\sqrt[]{7}\times14)-(3\sqrt[]{7}\times4\sqrt[]{56}) \\ (14\times3\sqrt[]{7})-3\sqrt[]{7}\times4\sqrt[]{4\times14} \\ (42\sqrt[]{7})-3\sqrt[]{7}\times8\sqrt[]{14} \\ (42\sqrt[]{7})-\lbrack(3\times8)\sqrt[]{7\times14} \\ 42\sqrt[]{7}-24\sqrt[]{98} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%203%5Csqrt%5B%5D%7B7%7D%2814-4%5Csqrt%5B%5D%7B56%7D%29%20%5C%5C%20%283%5Csqrt%5B%5D%7B7%7D%5Ctimes14%29-%283%5Csqrt%5B%5D%7B7%7D%5Ctimes4%5Csqrt%5B%5D%7B56%7D%29%20%5C%5C%20%2814%5Ctimes3%5Csqrt%5B%5D%7B7%7D%29-3%5Csqrt%5B%5D%7B7%7D%5Ctimes4%5Csqrt%5B%5D%7B4%5Ctimes14%7D%20%5C%5C%20%2842%5Csqrt%5B%5D%7B7%7D%29-3%5Csqrt%5B%5D%7B7%7D%5Ctimes8%5Csqrt%5B%5D%7B14%7D%20%5C%5C%20%2842%5Csqrt%5B%5D%7B7%7D%29-%5Clbrack%283%5Ctimes8%29%5Csqrt%5B%5D%7B7%5Ctimes14%7D%20%5C%5C%2042%5Csqrt%5B%5D%7B7%7D-24%5Csqrt%5B%5D%7B98%7D%20%5Cend%7Bgathered%7D)
Answer:1.6
Step-by-step explanation:Hope this helps