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anyanavicka [17]
3 years ago
8

How many molecules of ethanol (c2h5oh) (the alcohol in alcoholic beverages) are present in 160 ml of ethanol? the density of eth

anol is 0.789 g/cm3. n =?
Chemistry
1 answer:
jolli1 [7]3 years ago
3 0
Note: 1 ml = 1 cm^3

Density = mass / volume
mass = density x volume
mass = 0.789 x 160 = 126.24 grams

From the periodic table:
mass of carbon = 12 grams
mass of hydrogen = 1 grams
mass of oxygen = 16 grams
molar mass of ethanol = 2(12) + 5(1) + 16 +1 = 46 grams

number of moles = mass / molar mass
number of moles = 126.24 / 46 = 2.744 moles

Each mole contains Avogadro's number of molecules.
Therefore:
number of molecules = 2.744 x 6.02 x 10^23 = 1.6518 x 10^24 molecules
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a student needs to use 0.575 moles of sodium chloride in an experiment. How many grams should he mass out?
Bad White [126]

The molecular weight of NaCl is 58.44 g/mol.  

0.575 mol * 58.44 g/mol = 33.6 grams of NaCl

5 0
3 years ago
Ethene is a useful substance that can form polymers. It has a melting point of 169°C and a boiling point of 104°C. At which temp
blondinia [14]

Answer:

-169°C to -104°C

Explanation:

Ethene, also known as ethylene exists in solid, liquid and gaseous states. Ethene is an aliens with condensed structural formula C2H4. Athens is a colourless gas. It is flammable and is also a sweet smelling gas in its pure form. It is the monomer in the production of polyethylene which is of great importance in the plastic industry. In agriculture, it is used to induce the ripening of fruits. It can be hydrated in order to produce ethanol.

The liquid range of ethene refers to the temperatures at which ethene is found in the liquid state of matter. It is actually the difference between the melting point and the boiling points of ethene. Hence the liquid range of ethene is -169°C to -104°C

4 0
3 years ago
Which of the following statements describes the correct method of preparation of 1.00 L of a 2.0 M urea solution?
Zolol [24]

Answer:

To prepare 1.00 L of 2.0 M urea solution, we need to dissolve 120 g of urea in enough water to produce a total of 1.00 L solution

Explanation:

Molarity of a solute in a solution denotes number of moles of solute dissolved in 1 L of solution.

So, moles of urea in 1.00 L of a 2.0 M urea solution = 2 moles

We know, number of moles of a compound is the ratio of mass to molar mass of that compound.

So, mass of  2 moles of urea = (2\times 60.06)g=120 g

Therefore to prepare 1.00 L of 2.0 M urea solution, we need to dissolve 120 g of urea in enough water to produce a total of 1.00 L solution

So, option (C) is correct.

8 0
3 years ago
How many molecules are present in a drop of ethanol, c2h5oh, of mass 2.3*10^-2.3g? (NA=6.0*10^23mol^-1)
sdas [7]

Answer:

3.0 × 10²⁰ molecules

Explanation:

Given data:

Mass of ethanol = 2.3 × 10⁻²°³ g

Number of molecules = ?

Solution:

Number of moles of ethanol:

Number of moles = mass/ molar mass

Number of moles = 2.3 × 10⁻²°³ g / 46.07 g/mol

Number of moles = 0.05 × 10⁻²°³ mol

Number of molecules:

One mole = 6.022 × 10²³ molecules

0.05 × 10⁻²°³ mol  ×  6.022 × 10²³ molecules / 1 mol

0.30 × 10²⁰°⁷ molecules

3.0 × 10¹⁹°⁷ molecules which is almost equal to 3.0 × 10²⁰ molecules.

5 0
3 years ago
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xenn [34]

Answer:Macaya (floruit 1802), was a Kongolese-born Haitian revolutionary military leader. Macaya was one of the first black rebel leaders in Saint-Domingue to ally himself with the French Republican commissioners Sonthonax and Polverel. He helped to lead forces that recaptured Cap-Français on behalf of the French Republicans.

Macaya was born in west-central Africa, probably in the Kingdom of Kongo, and taken to the French colony of Saint-Domingue as a slave. After the outbreak of the 1791 slave rebellion in northern Saint-Domingue, Macaya became a lieutenant of an elderly rebel commander named Pierrot. Pierrot's rebel forces were based in the hills outside of Le Cap (Cap Francaise), near Bréda plantation by 1793.

Explanation:

7 0
2 years ago
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