The balanced equation for the reaction is as follows;
2Fe + 3S ---> Fe₂S₃
molar ratio of Fe to Fe₂S₃ is 2:1
mass of Fe₂S₃ to be produced is - 96 g
therefore number of moles of Fe₂S₃ to be produced is - 96 g / 208 g/mol
number of Fe₂S₃ moles = 0.46 mol
according to the molar ratio
when 2 mol of Fe reacts with 3 mol of sulfur then 1 mol of Fe₂S₃ is produced
that for 1 mol of Fe₂S₃ to be produced - 2 mol of Fe should react
therefore for 0.46 mol of Fe₂S₃ to be produced - 2 x 0.46 = 0.92 mol of Fe is required
mass of Fe required - 0.92 mol x 56 g/mol = 51.5 g
mass of Fe required is - 51.5 g
