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kirill [66]
3 years ago
12

What mass of iron is needed to react with sulfur in order to produce 96 grams of

Chemistry
2 answers:
Setler79 [48]3 years ago
8 0

The balanced equation for the reaction is as follows;

2Fe + 3S ---> Fe₂S₃

molar ratio of Fe to Fe₂S₃ is 2:1

mass of Fe₂S₃ to be produced is - 96 g

therefore number of moles of Fe₂S₃ to be produced is - 96 g / 208 g/mol

number of Fe₂S₃ moles = 0.46 mol

according to the molar ratio

when 2 mol of Fe reacts with 3 mol of sulfur then 1 mol of Fe₂S₃ is produced

that for 1 mol of Fe₂S₃ to be produced - 2 mol of Fe should react

therefore for 0.46 mol of Fe₂S₃ to be produced - 2 x 0.46  = 0.92 mol of Fe is required

mass of Fe required - 0.92 mol x 56 g/mol  = 51.5 g

mass of Fe required is - 51.5 g

Sladkaya [172]3 years ago
4 0

Answer:

103.2 g Fe

Explanation:

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