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kirill [66]
3 years ago
12

What mass of iron is needed to react with sulfur in order to produce 96 grams of

Chemistry
2 answers:
Setler79 [48]3 years ago
8 0

The balanced equation for the reaction is as follows;

2Fe + 3S ---> Fe₂S₃

molar ratio of Fe to Fe₂S₃ is 2:1

mass of Fe₂S₃ to be produced is - 96 g

therefore number of moles of Fe₂S₃ to be produced is - 96 g / 208 g/mol

number of Fe₂S₃ moles = 0.46 mol

according to the molar ratio

when 2 mol of Fe reacts with 3 mol of sulfur then 1 mol of Fe₂S₃ is produced

that for 1 mol of Fe₂S₃ to be produced - 2 mol of Fe should react

therefore for 0.46 mol of Fe₂S₃ to be produced - 2 x 0.46  = 0.92 mol of Fe is required

mass of Fe required - 0.92 mol x 56 g/mol  = 51.5 g

mass of Fe required is - 51.5 g

Sladkaya [172]3 years ago
4 0

Answer:

103.2 g Fe

Explanation:

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Toluene (C6H5CH3 ), an organic compound often used as a solvent in paints, is mixed with a similar organic compound, benzene (C6
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Explanation:

The given data is as follows.

 Weight of solute = 75.8 g,   Molecular weight of solute (toulene) = 92.13 g/mol,    volume = 200 ml

  • Therefore, molarity of toulene is calculated as follows.

      Molarity = \frac{\text{weight of solute}}{\text{molecular weight of solute}} \times \frac{1000}{\text{volume of solution in ml}}

                    = \frac{75.8 g}{92.13 g/mol} \times \frac{1000}{200 ml}

                    = 4.11 M

Hence, molarity of toulene is 4.11 M.

  • As molality is the number of moles of solute present in kg of solvent.

So, we will calculate the molality of toulene as follows.

   Molality = \frac{\text{given weight of solute}}{\text{given molecular weight of solute}} \times \frac{1000}{\text{weight of solvent in grams}}

             = \frac{75.8 g}{92.13 g/mol} \times \frac{1000}{95.6 g}

             = 8.6 m

Hence, molality of given toulene solution is 8.6 m.

  • Now, calculate the number of moles of toulene as follows.

       No. of moles = \frac{mass}{\text{molar mass}}

                             = \frac{75.8 g}{92.13 g/mol}

                             = 0.8227 mol

Now, no. of moles of benzene will be as follows.

     No. of moles = \frac{mass}{\text{molar mass}}

                             = \frac{95.6 g}{78.11 g/mol}

                             = 1.2239 mol

Hence, the mole fraction of toulene is as follows.

         Mole fraction = \frac{\text{moles of toulene}}{\text{total moles}}

                             = \frac{0.8227 mol}{(0.8227 + 1.2239) mol}

                             = 0.402

Hence, mole fraction of toulene is 0.402.

  • As density of given solution is 0.857 g/cm^{3} so, we will calculate the mass of solution as follows.

         Density = \frac{mass}{volume}

     0.857 g/cm^{3} = \frac{mass}{200 ml}      (As 1 cm^{3} = 1 g)

                      mass = 171.4 g

Therefore, calculate the mass percent of toulene as follows.

      Mass % = \frac{\text{mass of solute}}{\text{mass of solution}} \times 100

                   = \frac{75.8 g}{171.4 g} \times 100

                   = 44.22%

Therefore, mass percent of toulene is 44.22%.

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