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seraphim [82]
3 years ago
6

How are the cells of the bicep muscle similar to the cells of the heart muscle?

Chemistry
1 answer:
Brums [2.3K]3 years ago
4 0

Answer:

I believe it's D

Explanation:

they both are worked a lot and it makes the most sense.

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What is the mass in grams of 10 moles of ammonia, NH3?
8_murik_8 [283]

Answer:

C. 170 g.

Explanation:

multiply given moles by the molar mass of ammonia.

6 0
2 years ago
Both of janies parents have dark hair. how likely is janie to have blonde hair? ​
sveticcg [70]

Answer:

The probability of Janie to have blonde hair would be a slim 13% to a 34%.

Explanation:

Not 100% sure but best estimation I can come up with.

3 0
2 years ago
Two of the simplest compounds containing just carbon and hydrogen are methane and ethane. Methane contains 0.3357 g of hydrogen
Natasha_Volkova [10]
Let the ratio of grams of hydrogen per gram of carbon in methane be M, we know that:
M = 0.3357 g / 1 g

Next, lets represent the grams of hydrogen per gram of carbon in ethane be E. The final piece of information we have is:

M / E = 4/3

If we cross multiply,

3M = 4E

Now, substituting the value of M from earlier and solving for E,

E = (3 * 0.3357) / 4
E = 0.2518

There are 0.2518 grams of hydrogen per gram of carbon in ethane.
5 0
3 years ago
Using the image below, describe in at least 2 paragraphs, what is happening with the arrows. Name and explain the processes and
Eddi Din [679]

Answer: I'm sorry, but we can't see the image from NASA

Explanation:

6 0
3 years ago
HELP.
Kamila [148]

Answer:

The mass of tin is 164 grams

Explanation:

Step 1: Data given

Specific heat heat of tin = 0.222 J/g°C

The initial temeprature of tin = 80.0 °C

Mass of water = 100.0 grams

The specific heat of water = 4.184 J/g°C

Initial temperature = 30.0 °C

The final temperature = 34.0 °C

Step 2: Calculate the mass of tin

Heat lost = heat gained

Qlost = -Qgained

Qtin = -Qwater

Q = m*c*ΔT

m(tin)*c(tin)*ΔT(tin) = -m(water)*c(water)*ΔT(water)

⇒with m(tin) = the mass of tin = TO BE DETERMINED

⇒with c(tin) = the specific heat of tin = 0.222J/g°C

⇒with ΔT(tin) = the change of temperature of tin = T2 - T1 = 34.0°C - 80.0°C = -46.0°C

⇒with m(water) = the mass of water = 100.0 grams

⇒with c(water) = the specific heat of water = 4.184 J/g°C

⇒with ΔT(water) = the change of temperature of water = T2 - T1 = 34.0° C - 30.0 °C = 4.0 °C

m(tin) * 0.222 J/g°C * -46.0 °C = -100.0g* 4.184 J/g°C * 4.0 °C

m(tin) =  163.9 grams ≈ 164 grams

The mass of tin is 164 grams

4 0
3 years ago
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