Answer:
Explanation has been given below.
Explanation:
- A buffer consists of either of a weak acid along with it's conjugate base or a weak base along with it's conjugate acid.
- Let's consider a buffer consists of a weak acid along with it's conjugate base
- If we add an acid to this buffer then conjugate base gets protonated and converted to corresponding weak acid. So effect of addition of acid gets neutralized by forming weak acid rather than increase in concentration of proton in solution.
- If we add a base to this buffer then weak acid gets converted to corresponding conjugate base. So effect of addition of base gets neutralized by forming conjugate base rather than in crease in concentration of hydroxyl ion in solution.
Answer:
2.677 J/g°C
Explanation:
Quantity of heat required to raise the temperature of the metal,
Q = mc∆T
where m is the mass of the metal, c is the metal's specific heat capacity, and ∆T is the change in temperature that accompanies the heat transfer process
20.0J = 50.0g × c × 150°C
c = 20.0J/(50.0g × 150°C)
c = 2.677 J/g°C
If I am correct it should be nucleons
The frequency and energy of most energetic of these photons is
Hz and
J respectively.
The high energy photons will have least wavelength. Taking the given less wavelength for calculation of frequency and energy of photons.
λ = 2200 Å
Also, we know, 1 Å =
m
So, λ = 
λ =
<em> </em>m
Now, calculating frequency using the formula -
c = fλ, where c is speed of light, f is frequency and λ is wavelength.
We know, c =
m/s
f = c/λ
f = 
frequency =
Hz
Now, calculating Energy through the formula -
E = hf, where E is energy, h is planck's constant and f is frequency
Value of planck's constant =
Js
E =
*
Energy =
J
Thus, frequency and energy of photons is
Hz and
J respectively.
Learn more about energy of photon -
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5.732 grams of AgCl is formed when 0.200 L of 0.200 M AGNO3 reacts with an excess of CaCl2.
Explanation:
The balanced equation:
2 AgNO3(aq) + CaCl2(aq) -----> 2 AgCl(s) + Ca(NO3)2(aq)
data given:
volume of AgNO3 = 0.2 L
molarity of AgNO3 = 0.200 M
atomic weight of AgCl= 143.32 gram/mole
from the formula, number of moles can be calculated
Molarity = 
number of moles of AgNO3 = 0.04
From the reaction:
2 moles of AgNO3 reacts to form 2 moles of AgCl
0.04 moles of AgNO3 reacts to form x mole of AgCl
= 
= 0.04 moles of AgCl is formed
mass of AgCl formed is calculated by multiplying number of moles with atomic mass of AgCl
mass of AgCl = 0.04 x 143.32
= 5.732 grams of AgCl is formed.