<img src="https://tex.z-dn.net/?f=%20%5Ctextbf%20%7BSolve%20for%20x%20%3A%7D%20" id="TexFormula1" title=" \textbf {Solve for x :

All categories

Andre45 [30]

2 years ago

} " alt=" \textbf {Solve for x :} " align="absmiddle" class="latex-formula">

$\hookrightarrow \bf \: 2x + 5 = 9$

Mathematics

2 answers:

Vadim26 [7]2 years ago

8 0

Answer:

$\boxed{\sf x=2}$

Step-by-step explanation:

$\sf 2x+5=9$

Subtract 5 from both sides.

$\sf 2x+5-5=9-5$

$\sf 2x=4$

Divide both sides by 2.

$\sf \cfrac{2x}{2}=\cfrac{4}{2}$

$\sf x=2$

__________________

Komok [63]2 years ago

6 0

Answer:

x =2

Step-by-step explanation:

2x+5 =9

Subtract 5 from each side

2x+5-5 = 9-5

2x =4

Divide by 2

2x/2 =4/2

x =2

You might be interested in

SOMEONE HELP MEEE PLEASEEE !!

alisha [4.7K]

D pls, very simple :)

7 0

3 years ago

If the square root of x is greater than x then x could be

Shtirlitz [24]

Any decimal under 1, i believe.

8 0

4 years ago

Help plssssssssssssss

Svet_ta [14]

I believe it is option 2, sorry if incorrect

4 0

3 years ago

A regular 18-sided polygon is rotated with the center of rotation at its center. What is the smallest degree of rotation needed

dem82 [27]

It will be easier to explain how to solve this question in a square. If you rotate 4-sided square from the centre, you need to rotate it 90 degrees. The formula for this would be: 360 ° /the side count. In a square, it would be 360° /4= 90°.

In 18-sided polygon, the calculation would be: 360°/ 18 side= 20°

4 0

3 years ago

Read 2 more answers

Number 1 and 2 please (25 points)

Elenna [48]

Answers:

1) $(3x+2)+(4-5x)=-2x+6$

$(3+2i)+(4-5i)=7-3i$

2) $(1-3x)(2+x)=-3x^{2}-5x+2$

$(1-3i)+(2+i)=5-5i$

Step-by-step explanation:

In mathematics there are rules related to complex numbers, specifically in the case of addition and multiplication:

Addition:

If we have two complex numbers written in their binomial form, the sum of both will be a complex number whose real part is the sum of the real parts and whose imaginary part is the sum of the imaginary parts (similarly as the sum of two binomials).

For example, the addition of these two binomials is:

$(3x+2)+(4-5x)=3x-5x+2+4=-2x+6$

Similarly, the addition of two complex numbers is:

$(3+2i)+(4-5i)=3+4+2i-5i=7-3i$ Here the complex part is the number with the $i$

Multiplication:

If we have two complex numbers written in their binomial form, the multiplication of both will be the same as the multiplication (product) of two binomials, taking into account that $i^{2}=-1$ .

For example, the multiplication of these two binomials is:

$(1-3x)(2+x)=2+x-6x-3x^{2}=-3x^{2}-5x+2$

Similarly, the multiplication of two complex numbers is:

$(1-3i)+(2+i)=2+i-6i-3i^{2}=2-5i-3(-1)=5-5i$

8 0

3 years ago