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Andre45 [30]
2 years ago
9

} " alt=" \textbf {Solve for x :} " align="absmiddle" class="latex-formula">

\hookrightarrow \bf \: 2x + 5 = 9
​
Mathematics
2 answers:
Vadim26 [7]2 years ago
8 0

Answer:

\boxed{\sf x=2}

Step-by-step explanation:

\sf 2x+5=9

<u>Subtract 5 from both sides.</u>

  • <u />\sf 2x+5-5=9-5<u />
  • <u />\sf 2x=4<u />

<u>Divide both sides by 2.</u>

  • \sf \cfrac{2x}{2}=\cfrac{4}{2}
  • \sf x=2

__________________

Komok [63]2 years ago
6 0

Answer:

x =2

Step-by-step explanation:

2x+5 =9

Subtract 5 from each side

2x+5-5 = 9-5

2x =4

Divide by 2

2x/2 =4/2

x =2

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By proportional shapes, the side length of the top of the frustum can be found as follows;

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