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loris [4]
3 years ago
8

Last year a website had 40,000 visitors and this year it had 37,000 visitors.What is the percent change in the number of visitor

s to the website from last year to this year
Mathematics
1 answer:
Zarrin [17]3 years ago
4 0

Answer:

Step-by-step explanation:

The percent change formula is

original number - new number all divided by the original number times 100.  For us that looks like this:

\frac{40000-37000}{40000}*100 which simplifies to

\frac{3000}{40000}*100 which is a 7.5% decrease.

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A tree is 3 ft tall casts a shadow that is 2 ft long. Find the length of the shadow that a 6 ft tree cast.
AlladinOne [14]

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Step-by-step explanation:

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3 years ago
Marks own a carpet store and sells hallway runners for k9.52/linear foot. a) How much is this per linear yard? b) How much is th
Dimas [21]

Answer:

28.56/linear yard

32.2256/linear meter

121.77984k

Step-by-step explanation:

a) Scale = k9.52*3 = 28.56/linear yard

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6 0
3 years ago
50 Points!
Lesechka [4]

Answer:

D 1/4

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Deluxe River Cruises operates a fleet of river vessels. The fleet has two types of vessels: A type-A vessel has 60 deluxe cabins
bixtya [17]

Answer: It should be used 2 for type-A and 3 for type-B to minimize the cost.

Step-by-step explanation: As it is stipulated, <u>x</u> relates to type-A and y to type-B.

Type-A has 60 deluxe cabins and B has 80. It is needed a minimum of 360 deluxe cabins, so:

60x + 80y ≤ 360

For the standard cabin, there are in A 160 and in B 120. The need is for 680, so:

160x + 120y ≤ 680

To calculate how many of each type you need:

60x + 80y ≤ 360

160x + 120y ≤ 680

Isolating x from the first equation:

x = \frac{360 - 80y}{60}

Substituing x into the second equation:

160(\frac{360 - 80y}{60}) + 120y = 680

-3200y+1800y = 10200 - 14400

1400y = 4200

y = 3

With y, find x:

x = \frac{360 - 80y}{60}

x = \frac{360 - 80.3}{60}

x = 2

To determine the cost:

cost = 42,000x + 51,000y

cost = 42000.2 + 51000.3

cost = 161400

To keep it in a minimun cost, it is needed 2 vessels of Type-A and 3 vessels of Type-B, to a cost of $161400

8 0
3 years ago
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