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aalyn [17]
3 years ago
11

Easy question There are 8 sixth-graders and 16 seventh-graders in a class.

Mathematics
2 answers:
Vika [28.1K]3 years ago
8 0

Answer:

2 seventh graders

Step-by-step explanation:

8:16 simplified=1:2

therefore for every 1 sixth-grader there is 2 seventh graders

fenix001 [56]3 years ago
8 0

Answer:

there is 1 sixth grader for every 2 seventh graders

Step-by-step explanation:

there are 16 seventh graders divided by the 8 sixth graders= 2 seventh graders per sixth grader

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A+surveyor+leaves+her+bade+camp+and+drives+42km+on+abearing+of+032°.+She+then+drives+28km+on+a+bearing+of+154°.+How+far+is+she+f
professor190 [17]

Answer:

36.078km

253.2°

Step-by-step explanation:

Distance from her base camp could be calculated using the cosine rule:

And the angle calculated using the sine rule

AB = c = 42 KM, BC = a = 28 KM, AC = b =?

7 0
3 years ago
Read 2 more answers
Factor 125x9 64. (5x3 – 4)(25x6 20x3 16) (5x3 – 4)(25x3 20x3 16) (5x3 4)(25x6 – 20x3 16) (5x3 4)(25x3 – 20x3 16).
MatroZZZ [7]

The factorization of \rm 125x^9 + 64 is  \rm (5x^3 + 4)(25x^6 - 20x^3 +16).

<h3>Factorization;</h3>

Factorization is nothing but writing a number as the product of smaller numbers.

Given

Polynomial; \rm 125x^9 + 64

To find the factorization the polynomial equates the equation with zero following all the steps given below.

Then,

The factor of the polynomial is;

\rm= 125x^9 + 64\\\\= 125x^9 -100x^6+80x^3+100x^6-80x^3+64 \\\\ =5x^3(25x^6 - 20x^3 +16) +4(25x^6 - 20x^3 +16) \\\\=(5x^3 + 4)(25x^6 - 20x^3 +16)

Hence, the factorization of \rm 125x^9 + 64 is  \rm (5x^3 + 4)(25x^6 - 20x^3 +16).

To know more about factorization click the link given below.

brainly.com/question/17595467

3 0
2 years ago
Please help me thank you
frosja888 [35]
Hey, i have no idea what the question is but i hope you have a great day!
7 0
2 years ago
Can you please tell me how to do easy way can you please show me in numbers how to multiply ​
almond37 [142]

same as before, we look at the denominators, hmmm do a quick prime factoring.

3 = 3 * 1

9 = 3 * 3 * 1

since 9 already contains 3 and 1, we can us that

\cfrac{\underline{2}}{3}~~ - ~~\cfrac{1}{9}\implies \cfrac{(2)\underline{2}~~ - ~~(1)1}{\underset{\textit{using this LCD}}{9}}\implies \cfrac{4-1}{9}\implies \cfrac{\stackrel{1}{~~\begin{matrix} 3 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}}{\underset{3}{~~\begin{matrix} 9 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}}\implies \cfrac{1}{3}

4 0
3 years ago
Is this a function? if so what’s the domain and range. PLZ help plz
mars1129 [50]
No because it clearly fails the vertical line test
5 0
3 years ago
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