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1 year ago

11

Leah just moved and she's looking for a new dance studio. She gets to list the price from tip top toes charges $300 for 12 class

es and groovin amd movin charges $264 11 classes which studio offers the better deal?

1 answer:

SpyIntel [72]1 year ago

8 0

If it’s by week then groovin and movin,but if it’s months tip toes

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Is the point (1,3) a solution to the linear equation 5x-9y=32? explain

harina [27]

There are many ways to check if the point (1,3) is a solution to the linear equation $5x-9y=32$ .

Let us check it by expressing y in terms of x.

The given expression is 5x-9y=32. If we add -5x to both sides we will get:

$-9y=-5x+32$

Multiplying both sides by -1 we will get:

$9y=5x-32$

In order to isolate y, we will divide both sides by 9 to get:

$y=\frac{5}{9}x-\frac{32}{9}$

Now let us plug in the given value of x=1 from the point (1,3). This should give us y=3. Let us see if we get y=3 when we plug x=1 in the above equation.

$y=\frac{5}{9}\times 1-\frac{32}{9}=\frac{5-32}{9}$

$\therefore y=\frac{-27}{9}=-3$

Thus, we see that when x=1, y=-3 and that $y\neq 3$ and hence we conclude that the point (1,3) is not a solution to the original given linear equation 5x-9y=32.

For a better understanding of the explanation given here a graph has been attached. As can be seen from the graph, (1,3) does not lie on the straight line that represents 5x-9y=32, but (1,-3) does lie on it as we had just found out.

3 0

3 years ago

Read 2 more answers

Which is the equation of a hyperbola with directrices at x = ±3 and foci at (4, 0) and (−4, 0)?

Alex Ar [27]

Answer:

$\frac{x^2}{12}-\frac{y^2}{4}=1$

Step-by-step explanation:

Since our foci are located on the x-axis, then our major axis is going to be the horizontal transverse axis of the hyperbola:

<u>Formula for hyperbola with horizontal transverse axis centered at origin</u>

<u /> $\frac{x^2}{a^2}-\frac{y^2}{b^2}=1$
Directrices -> $x=\pm\frac{a^2}{c}$
Foci -> $(\pm c,0)$ where $a^2+b^2=c^2$
$a>b$

Since we are given our directrices of $x=\pm3$ and foci of $(\pm4,0)$ , then we can set up the directrices equation to solve for $a^2$ :

$x=\pm\frac{a^2}{c}\\ \\\pm3=\pm\frac{a^2}{4}\\ \\12=a^2$

Now we can determine $b^2$ to complete our equation for the hyperbola:

$a^2+b^2=c^2\\\\12+b^2=4^2\\\\12+b^2=16\\\\b^2=4$

Therefore, our equation for our hyperbola is $\frac{x^2}{12}-\frac{y^2}{4}=1$

5 0

2 years ago

Please help idk the right answer

kompoz [17]

Answer:

C

Step-by-step explanation:

if you add the value if f(x) to t

8 0

3 years ago

3 1/7 x 10 answer plz

Yanka [14]

Answer:

31.43

Step-by-step explanation:

3 1/7 = 3.14285714285

3 1/7 x 10 = 31.4285714286 which is about 31.43

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2 years ago

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You spend two and a half hours online you spend one fifth of that time writing a blog how long do you spend writing your blog

sveta [45]

Answer:

u spend half an hour on your blog

Step-by-step explanation:

(1/5)*(5/2) = 1/2

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2 years ago