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Tanya [424]
2 years ago
15

This table represents a proportional relationship.

Mathematics
1 answer:
Yanka [14]2 years ago
7 0

Answer:

x 2 4 <u>6</u> 7 9

y 1 2 3 3.5 <u>4.5</u>

This is the answer :) I hope it helps.

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Triangle XYZ, XY= 80, ZY= 64 XZ= 48 what is the cosine
SVETLANKA909090 [29]

Answer:

cos=\frac{4}{5}

Step-by-step explanation:

Cosine is the adjacent side over the hypotenuse (You can remember sin, cos, and tan by using sohcahtoa or sin = opposite/hypotenuse, cos = adjacent/hypotenuse, tan = opposite over adjacent). I think a picture would help, too.

I attached a picture of what I think the triangle would look like.

If the picture is right (we're assuming it is) and going with what we're given (the triangle was addressed as triangle XYZ, meaning that <u>angle Y is in the middle and that's the one we'll use</u>).

Looking at my picture then:

cos=\frac{64}{80} \\cos=\frac{8}{10} \\cos=\frac{4}{5} .

6 0
3 years ago
Please help!!!<br><br> 3(x – 10) = -9
sergey [27]

Answer:

The answer is x = 7

Step-by-step explanation:

Divide each term by  3  and simplify. Move all terms not containing  x  to the right side of the equation.

3 0
3 years ago
Read 2 more answers
5y^2+5−4−4y^2+5y^2−4x^3 −1
vredina [299]

Answer:

\boxed{ \bold{ \huge{ \boxed{ \sf{4 {x}^{3}  + 6 {y}^{2} }}}}}

Step-by-step explanation:

\sf{5 {y }^{2}  + 5 - 4 - 4 {y}^{2}  + 5 {y}^{2}  - 4 {x}^{3}  - 1}

Collect like terms

⇒\sf{ 4 {x}^{3}  + 5 {y}^{2}  - 4 {y}^{2}  + 5 {y}^{2}  + 5 - 4 - 1}

⇒\sf{4 {x}^{3}  +  {y}^{2}  + 5 {y}^{2}  + 5 - 4 - 1}

⇒\sf{4 {x}^{3}  + 6 {y}^{2}  + 5 - 4 - 1}

Calculate

⇒\sf{4 {x}^{3}  + 6 {y}^{2}  + 1 - 1}

⇒\sf{4 {x}^{3}  + 6 {y}^{2} }

Hope I helped!

Best regards! :D

6 0
3 years ago
Help plzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzz 10 points
Dafna1 [17]

Answer:

C≈18.85

Step-by-step explanation:

have a nice day!

3 0
3 years ago
A farmers field has the dimensions shown. He needs to find the area of the field so that he knows how much he needs to buy .What
kolbaska11 [484]

Answer:

Area of the rectangular Field = 3 8/9 km²

Step-by-step explanation:

Length of the field = 2 1/3 km

Width of the field = 1 2/3 km

Area of a rectangular Field = length × width

= 2 1/3 × 1 2/3

= 7/3 × 5/3

= (7*5)/(3*3)

= 35/9

Area of the rectangular Field = 3 8/9 km²

Perimeter of the rectangular Field = 2(length + width)

= 2(2 1/3 + 1 2/3)

= 2(7/3 + 5/3)

= 2(7+5/3)

= 2(12/3)

=2(4)

= 8 km

Perimeter of the rectangular Field = 8 km

5 0
3 years ago
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