Tsquare= Ksquare +Vsquare -2(K)(V) times cosT
I believe it would be 0 fr
Answer:
x = 2
y = -3
z = 4
( 2 , -3, 4 )
Step-by-step explanation:
x + y + z = 3 ---- i
x – y =5 ---- ii
y - z = -7 ---- iii
ii + iii
x - z = -2 ---- iv
i + ii
2x + z = 8 --- v
iv + v
3x = 6
x = 2
x=2 substitute for v
z = 4
x =2 substitute for ii
y = -3
What are the dimensions of the building?
