The first equation
6x^2 -18x-24=0
-the graph opens up
6(x^2 -3x -4)=0
6(x^2 -3x +9/4-4-9/4)=0
6(x-3/2)-25x6/4=
6(x-3/2)-75/2
-Vertex is at (3/2, -75/2)
-Axis of symmetry is x=3/2
Second equation
3r^2 -16r -12=0
-the graph opens up
...
From what I got there is one real solution :)
Rearrange the second equation to give y=2-2x, substitute into the first equation to give you a value for x and then using that you can work out y for the exact coordinates of intersection :)
Also they are both straight line graphs so they will either have one or no solutions
Hope this helped :)
Answer:
Note that both relations and functions have domains and ranges. The domain is the set of all first elements of ordered pairs (x-coordinates). The range is the set of all second elements of ordered pairs (y-coordinates). Only the elements "used" by the relation or function constitute the range.
Answer:
the point
Step-by-step explanation:
the point makes a decimal a decimal
