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1 year ago

I will mark brainliest!

Mathematics

1 answer:

Triss [41]1 year ago

7 0

Answer:

see below

Step-by-step explanation:

Just graph y = 4/5 x

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Help, please Jake has $100 of birthday money in his wallet. He spends $15 at Twistee Treat and $10 at Wawa. While walking home h

Alchen [17]

Answer:

The expression is $x=100-15-10+20-40+35$

Jake has in his wallet $\$90$

Step-by-step explanation:

Let

x-----> the money that Jake has in his wallet

we know that

The expression that represent the situation is equal to

1) Jake has $100 of birthday money in his wallet

$x=100$

2) He spends $15 at Twistee Treat and $10 at Wawa

$x=100-15-10$

3) He finds a $20 bill on the ground

$x=100-15-10+20$

3) His friend borrows $40 from Jake

$x=100-15-10+20-40$

4) At home, Jake mows the lawn and earns $35

$x=100-15-10+20-40+35$

$x=\$90$

5 0

3 years ago

Evaluate the following expression using the values given: Find −a2 − 3b3 + c2 + 2b3 − c2 if a = 3, b = 2, and c = −3. (1 point)

wariber [46]

The answer is -12
because you just have to simplyfy it and plug in the values

6 0

3 years ago

LMN≅PQR What is the value of x in degrees?

astra-53 [7]

180-39-55=86°
...........................

5 0

3 years ago

Read 2 more answers

Jing makes a cut through a block of butter, as shown. What are the

levacccp [35]

Answer: C) 4 x 3 cm

Step-by-step explanation:

The only dimension affected by the cut was 5, because the cut was perfectly parallel to the 4x3 face.

6 0

3 years ago

An electric sale gives a reading equal to the true weight plus a random error that isnormally distributed with mean 0 and standa

Pepsi [2]

Answer:

a) 95% confidence interval estimate of the true weight is (3.026, 3.274)

b) 99% confidence interval estimate of the true weight is (2.944, 3.356)

Step-by-step explanation:

Confidence Interval can be calculated using M±ME where

M is the mean of five successive weightings (3.150)

ME is the margin of error from the mean

And margin of error (ME) can be calculated using the formula

ME= $\frac{t*s}{\sqrt{N} }$ where

t is the corresponding statistic in the given confidence level and degrees of freedom(t-score)

s is the standard deviation of the random error (0.1)

N is the sample size (5)

Using the numbers 95% confidence interval estimate of the true weight is:

3.150± $\frac{2.776*0.1}{\sqrt{5} }$ ≈3.150±0.124

And 99% confidence interval estimate of the true weight is:

3.150± $\frac{4.604*0.1}{\sqrt{5} }$ ≈3.150±0.206

3 0

3 years ago