4 years ago

Somebody please help me

Mathematics

1 answer:

lara31 [8.8K]4 years ago

5 0

-6 ≥ 10 - 8x Subtract 10 from both sides
-16 ≥ -8x Divide by -8 to both sides
x ≥ 2 your answer is c

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Hi please i nedd help with these questions .

Vlad1618 [11]

Answer:

Step-by-step explanation:

#1:

$\frac{18m^2u}{16n^3v^2} \div \frac{24m}{15nu^3}*\frac{8n^2v^3}{30m^3u}$

division sign means that we flip the fraction

$\frac{18m^2u}{16n^3v^2} * \frac{15nu^3}{24m}*\frac{8n^2v^3}{30m^3u}$

now we can multiply all the constants together and all variables

$m: (m^2)/(m*m^4) = (m^2)/(m^4) = 1/(m^2)\\u: (u * u^3)/(u) = (u^4)/(u) = u^3\\n: (n*n^2)/(n^3) = 1\\v: (v^3) / (v^2) = v\\(18*15*8)/(16*24*30) = \frac{3}{16}$

now we can combine all the parts

$\frac{3u^3v}{16m^2}$

#2:

$\frac{24a^2b^3c}{9bc^3}\div\frac{4a^5bc^3}{27a^3b^2c}$

$\frac{24a^2b^3c}{9bc^3}*\frac{27a^3b^2c}{4a^5bc^3}$

$a: (a^2 * a^3)/(a^5) = 1\\b: (b^3 *b^2)/(b*b) = b^3\\c: (c*c)/(c^3*c^3)= 1/(c^4)\\(24*27)/(9*4)= 18$

$\frac{18b^3}{c^4}$

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