Question

Can anyone help me please

Answer 1

Step-by-step explanation:

as the formula says for the acid of symmetry :

x = -b/2a

in the function m(x) = 2x² + 8x +3

we have

a = 2

b = 8

c = 3

the axis of symmetry is

x = -8/(2×2) = -8/4 = -2

the vertex is (h, k) out of the form

m(x) = a(x - h)² + k

we know already, a = 2

for the rest we do all the multiplications and then we compare it with the original function :

m(x) = a(x² - 2hx + h²) + k = ax² - 2ahx + ah² + k

a = 2

-2ah = 8

-2×2×h = 8

-4h = 8

h = -2

ah² + k = 3

2×(-2)² + k = 3

8 + k = 3

k = -5

so, the vertex is (-2, -5)