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Vikentia [17]
3 years ago
6

Probablity of getting a number greater than 4 when a die is rolled one time

Mathematics
2 answers:
RoseWind [281]3 years ago
6 0

Answer:

2/6

Step-by-step explanation:

There are 6 numbers on a regular die, and only 2 numbers that are greater than four that you could get, so the probability of getting a number greater then 4 would be 2/6

arsen [322]3 years ago
3 0

Answer:

A = {5,6}. The probability that the result of one die roll is greater than 4 is the number of events in set A divided by the total number of possible outcomes (the size of the sample space S) and so the probability of getting a number greater than 4 on one die roll is which reduces to . Answer: ... A dice is rolled twice.

Step-by-step explanation:

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Alenkasestr [34]

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Step-by-step explanation:

The correct answer doesn't seem to be listed...

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8 0
3 years ago
Read 2 more answers
Simplify the expression (8x^3y^2/4a^2b^4)^-2
icang [17]
Simplify the following:
((8 x^3 y^2 a^2 b^4)/4)^(-2)
8/4 = (4×2)/4 = 2:
(2 x^3 y^2 a^2 b^4)^(-2)
Multiply each exponent in 2 x^3 y^2 a^2 b^4 by -2:
(x^(-2×3) y^(-2×2) a^(-2×2) b^(-2×4))/(2^2)
-2×3 = -6:
(x^(-6) y^(-2×2) a^(-2×2) b^(-2×4))/2^2
-2×2 = -4:
(y^(-4) a^(-2×2) b^(-2×4))/(2^2 x^6)
-2×2 = -4:
(a^(-4) b^(-2×4))/(2^2 x^6 y^4)
-2×4 = -8:
b^(-8)/(2^2 x^6 y^4 a^4)
2^2 = 4:
Answer: 1/(4 x^6 y^4 a^4 b^8) thus the answer is A
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3 years ago
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