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Vikentia [17]
3 years ago
6

Probablity of getting a number greater than 4 when a die is rolled one time

Mathematics
2 answers:
RoseWind [281]3 years ago
6 0

Answer:

2/6

Step-by-step explanation:

There are 6 numbers on a regular die, and only 2 numbers that are greater than four that you could get, so the probability of getting a number greater then 4 would be 2/6

arsen [322]3 years ago
3 0

Answer:

A = {5,6}. The probability that the result of one die roll is greater than 4 is the number of events in set A divided by the total number of possible outcomes (the size of the sample space S) and so the probability of getting a number greater than 4 on one die roll is which reduces to . Answer: ... A dice is rolled twice.

Step-by-step explanation:

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Can someone pls graph the picture below.
grin007 [14]

Answer:

  see below

Step-by-step explanation:

This graphs as 3 horizontal lines. The open circles are at the ends of the interval where the function is undefined or is defined as a different value.

3 0
3 years ago
x = c1 cos(t) + c2 sin(t) is a two-parameter family of solutions of the second-order DE x'' + x = 0. Find a solution of the seco
igomit [66]

Answer:

x=-cos(t)+2sin(t)

Step-by-step explanation:

The problem is very simple, since they give us the solution from the start. However I will show you how they came to that solution:

A differential equation of the form:

a_n y^n +a_n_-_1y^{n-1}+...+a_1y'+a_oy=0

Will have a characteristic equation of the form:

a_n r^n +a_n_-_1r^{n-1}+...+a_1r+a_o=0

Where solutions r_1,r_2...,r_n are the roots from which the general solution can be found.

For real roots the solution is given by:

y(t)=c_1e^{r_1t} +c_2e^{r_2t}

For real repeated roots the solution is given by:

y(t)=c_1e^{rt} +c_2te^{rt}

For complex roots the solution is given by:

y(t)=c_1e^{\lambda t} cos(\mu t)+c_2e^{\lambda t} sin(\mu t)

Where:

r_1_,_2=\lambda \pm \mu i

Let's find the solution for x''+x=0 using the previous information:

The characteristic equation is:

r^{2} +1=0

So, the roots are given by:

r_1_,_2=0\pm \sqrt{-1} =\pm i

Therefore, the solution is:

x(t)=c_1cos(t)+c_2sin(t)

As you can see, is the same solution provided by the problem.

Moving on, let's find the derivative of x(t) in order to find the constants c_1 and c_2:

x'(t)=-c_1sin(t)+c_2cos(t)

Evaluating the initial conditions:

x(0)=-1\\\\-1=c_1cos(0)+c_2sin(0)\\\\-1=c_1

And

x'(0)=2\\\\2=-c_1sin(0)+c_2cos(0)\\\\2=c_2

Now we have found the value of the constants, the solution of the second-order IVP is:

x=-cos(t)+2sin(t)

3 0
3 years ago
Determine the inverse of a function. please help!​
Brums [2.3K]
This is what i got!!
8 0
3 years ago
?/6=1/2 Will get Brainliest
IgorC [24]

Answer:

3/6

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Damien , Jake , and Makayla shared a bowl of grapes . Damien ate x grapes . Jake ate 1 more than twice the number of grapes that
vivado [14]

Answer:

There were (4x + 2) grapes in the bowl

Step-by-step explanation:

Here, we are interested in calculating the total number of grapes in the bowl.

We have 3 people sharing the total

Damien are x grapes

Jake ate 1 more than twice what Damien and that is (1 + 2x) grapes

Makayla ate 5 fewer grapes than Damien: So what Makayla ate is (x-5) grapes

And now, we have 6 grapes left.

To find the total number of grapes in the bowl, we need to add up all what they ate plus what is left.

Mathematically, that would be;

x + 1 + 2x + x -5 + 6

= 4x + 2

8 0
3 years ago
Read 2 more answers
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